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Elanso [62]
3 years ago
8

What is the pH of 5.0 L of an aqueous solution that contains 1.0 grams of HBr and 1.0 grams of nitric acid

Chemistry
1 answer:
Nady [450]3 years ago
8 0

Hello!:

Molar mass:

HBr = 80.91 g/mol

HNO3 = 63.01 g/mol

Number of moles:

moles HBr =  1.0 / 80.91 => 0.01235 moles of HBr

moles HNO3 = 1.0 / 63.01 => 0.01587 moles of HNO3

So , total moles of H⁺ :

0.01235 + 0.01587 => 0.02822 moles of H⁺

Molarity of solution:

M = n / V

M = 0.02822 / 5.0

M = 0.005644

Therefore:

pH = - log [ H⁺ ]

pH = - log [ 0.005644 ]

pH = 2.25


Hope that helps!


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Alkynes have what in<br> common with alkenes ?
jonny [76]

Answer:

Alkanes, alkenes and alkynes are simple hydrocarbon chains with no functional groups. Alkanes are identified because the carbon chain has only single bonds. Alkenes have at least one double bond and alkynes have at least one triple bond. The most common alkyne is ethyne, better known as acetylene.

8 0
3 years ago
Boron is to the immediate left of carbon in the same row in the periodic table. Which of the following statements compares the r
natita [175]

Answer:

Boron has a larger radius and the protons in carbon exert more pull.

Explanation:

Remember than elements have greater radius as they are closer to the bottom left corner, so boron would have the larger radius here. Carbon has a smaller radius, which makes it easier for the protons in carbon to exert more pull.

7 0
3 years ago
Read 2 more answers
What is the overall enthalpy of reaction for the equation shown below?
Rudiy27

Answer:

ΔH₁₂ = -867.2 Kj

Explanation:

Find enthalpy for 3H₂ + O₃ => 3H₂O given ...

2H₂ + O₂ => 2H₂O      ΔH₁ = -483.6 Kj

        3O₂ => 2O₃        ΔH₂ = + 284.6 Kj

_____________________________

3(2H₂ + O₂ => 2H₂O) => 6H₂ + 3O₂ => 6H₂O       (multiply by 3 to cancel O₂)

6H₂ + 3O₂ => 6H₂O        ΔH₁ = 3(-483.6 Kj) = -1450.6Kj

          2O₃ => 3O₂           ΔH₂ = -284.6Kj              (reverse rxn to cancel O₂)

_______________________________

6H₂ + 2O₃ => 6H₂O         ΔH₁₂ = -1735.2 Kj       (Net Reaction - not reduced)

________________________________

divide by 2 => target equation (Net Reaction - reduced)

3H₂ + O₃ => 3H₂O            ΔH₁₂ = (-1735.2/2) Kj = -867.2 Kj    

4 0
3 years ago
A substance decays so that the amount a of the substance left at time t is given by: a = a0 ∙ (0.8)t where a0 is the original am
Zolol [24]

The half-life of the substance is 3.106 years.

<h3>What is the formula for exponential decay?</h3>
  • The exponential decline, which is a rapid reduction over time, can be calculated with the use of the exponential decay formula.
  • The exponential decay formula is used to determine population decay, half-life, radioactivity decay, and other phenomena.
  • The general form is F(x) = a.

Here,

a = the initial amount of substance

1-r is the decay rate

x = time span

The equation is given in its correct form as follows:

a = a_{0}×(0.8)^{t}

As this is an exponential decay of a first order reaction, t is an exponent of 0.8.

Now let's figure out the half life. Since the amount left is half of the initial amount at time t, that is when:

a = 0.5 a0

<h3>Substituting this into the equation:</h3>

0.5a_{0} = a_{0}×(0.8)^{t}

0.5 = (0.8)^{t}

taking log on both sides

t log 0.8 = log 0.5

t = log 0.5/log 0.8

t = 3.106 years

The half-life of the substance is 3.106 years.

To learn more about exponential decay formula visit:

brainly.com/question/28172854

#SPJ4

4 0
1 year ago
Identify the acid-conjugate base pair in this balanced equation:
Nataliya [291]

Answer:

The answer is B. H2SO4/Na2SO4

Explanation:

5 0
3 years ago
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