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marusya05 [52]
3 years ago
12

What type of reaction happens inside a nuclear power plant?

Chemistry
1 answer:
brilliants [131]3 years ago
7 0
Hello the answer is C i hope this helps you
You might be interested in
How would the world be different if people were not aware of radioactive decay
allsm [11]

Answer:

everyone would die

Explanation:

if we did not know about it we would not do anything about it

6 0
3 years ago
If a 1.00 mL sample of the reaction mixture for the equilibrium constant experiment required 32.40 mL of 0.258 M NaOH to titrate
andrey2020 [161]

Answer:

The concentration of acetic acid is 8.36 M

Explanation:

Step 1: Data given

Volume of acetic acid = 1.00 mL = 0.001 L

Volume of NaOH = 32.40 mL = 0.03240 L

Molarity of NaOH = 0.258 M

Step 2: The balanced equation

CH3COOH + NaOH → CH3COONa + H2O

Step 3: Calculate the concentration of the acetic acid

b*Ca*Va = a*Cb*Vb

⇒with b = the coefficient of NaOH = 1

⇒with Ca = the concentration of CH3COOH = TO BE DETERMINED

⇒with Va = the volume of CH3COOH = 1.00 mL = 0.001L

⇒with a = the coefficient of CH3COOH = 1

⇒with Cb = the concentration of NaOH = 0.258 M

⇒with Vb = the volume of NaOH = 32.40 mL = 0.03240 L

Ca * 0.001 L = 0.258 * 0.03240

Ca = 8.36 M

The concentration of acetic acid is 8.36 M

6 0
3 years ago
What is the mass of an object that has a density of 0.500 g/cm3 and a volume of 5.00 mL?
attashe74 [19]

Answer:

<h2>The answer is 2.5 g</h2>

Explanation:

The mass of a substance when given the density and volume can be found by using the formula

<h3>mass = Density × volume</h3>

From the question

density = 0.5 g/cm³

1 mL = 1 cm³

5 mL = 5 cm³

volume = 5 cm³

The mass is

mass = 0.5 × 5

We have the final answer as

<h3>2.5 g</h3>

Hope this helps you

4 0
3 years ago
Help me fill in the blanks
Studentka2010 [4]
First blank -Same
Second blank-Neutral
5 0
4 years ago
The pka value for the carboxylic acid group in acetic acid is 4.75. write the predominant structure of acetic acid at (a ph=1, (
Scorpion4ik [409]
Hello!

A) At pH=1

This pH is lower than the value for the pKa, so Acetic acid wouldn't be ionized, but the equilibrium would be displaced to CH₃COOH

CH₃COOH ⇄ CH₃COO⁻ + H₃O⁺ (equilibrium displaced to the left)

The chemical structure for CH₃COOH is the first one in the attached images.

B) At pH=7

This pH is higher than the value for the pKa, so Acetic acid would be ionized, and the equilibrium would be displaced to CH₃COO⁻

CH₃COOH ⇄ CH₃COO⁻ + H₃O⁺ (equilibrium displaced to the right)

The chemical structure for CH₃COO⁻ is the second one in the attached images.

Have a nice day!

7 0
3 years ago
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