Question

What is the value of the expression? 8 and one-half minus 2 + 4 and three-fourths

Answer 1

Answer:

11 and one fourth.

or

$11\dfrac{1}{4}$

Step-by-step explanation:

Given the expression to be solved:

8 and one-half minus 2 + 4 and three-fourths

Let us solve them step by step:

8 and one-half can be represented as:

$8\dfrac{1}{2}$

Method to solve a mixed fraction of the form $p\frac{q}{r}$ is:

$p\dfrac{q}{r} = \dfrac{p\times r+q}{r}$

$8\dfrac{1}{2}= \dfrac{8 \times 2+1}{2} = \dfrac{17}{2}$

Similarly, solving 4 and three-fourths:

$4\dfrac{3}{4} = \dfrac{4 \times 4+3}{4} = \dfrac{19}{3}$

Now, the given expression:

$8\dfrac{1}{2}-2+4\dfrac{3}{4}$

$\Rightarrow \dfrac{17}{2} -2+\dfrac{19}{4}\\\Rightarrow \dfrac{17 \times 2-2 \times 4+19\times 1}{4}\\\Rightarrow \dfrac{34-8+19}{4}\\\Rightarrow \dfrac{45}{4}\\\Rightarrow 11\dfrac{1}{4}$

So, the answer is 11 and one fourth.