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MrRa [10]
3 years ago
9

Sir Lance a Lost new draw bridge was designed poorly and stops at an angle of 20o below the horizontal. Sir Lost and his steed s

top when their combined center of mass is 1.0 m from the end of the bridge. The bridge is 8.0 m long and has a mass of 2000 kg; the lift cable is attached to the bridge 5.0 m from the castle end and to a point 12 m above the bridge. Sir Lost’s mass combined with his armor and steed is 1000 kg.
Determine
(a) the tension in the cable and
(b) the horizontal and vertical force components acting on the bridge at the castle end.

Physics
1 answer:
zloy xaker [14]3 years ago
4 0

Answer:

The Tension T is 42120N

The Horizontal force component is 18322.2N

The Vertical force component is - 4729N

Explanation:

First, you have to find the angle between the drawbridge and the cable using sine and cosine rule. This will result in angle 44.2°. Hence, the angle between the horizontal axis and the cable will be 64.2° (44.2° + 20°).

Having done that, you apply two conditions of equilibrium.

1. THE VECTOR SUM OF ALL FORCES EQUAL ZERO.

∑Fx = 0

∑Fx = Rx - Tcos64.2 = 0

Rx = 0.435T

∑Fy = 0

∑Fy = Ry + Tsin64.2 - W - w = 0

W = 2000kg × 9.8 = 19600N

w =1000kg × 9.8 = 9800N

Ry + 0.9T = 29400N

Ry = 29400 - 0.9T

2. THE SUM TOTAL OF TORQUES EQUALS ZERO

Rx: τ = 0

Ry: τ = 0

T: τ = 5 × Tsin44.2

= 3.49T m

W: τ = 4 × 19600sin90

= 78400Nm

w: τ = 7 × 9800sin9

= 68600Nm

Note:

Rx = x component of Reaction force

Ry = y component of Reaction force.

T = Tension

W = weight of bridge

w = weight of Sir Lance a Lost and his steed

τ = torque

Note: The torque of Tension is counter clockwise while that of the weights is clockwise.

Hence,

∑τccw = ∑τcw

3.49T = 78400 + 68600

3.49T = 14700Nm

T = 147000/3.49

T = 42120N

Rx = 0.435 × 42120

Rx = 18322.2N

Ry = 29400N - (0.9×42120)N

Ry = 29400 - 34129

Ry = -4729N

Note: Ry being negative means that the hinge of the drawbridge exerts a downward force.

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2 years ago
a desktop computer and monitor together draw about 2 A of current they plug into a wall outlet that is 120 V what is the Resista
Delvig [45]

Answer:

60 \Omega

Explanation:

the relation between current, voltage and resistance in an electrical circuit is given by Ohm's law:

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where V is the voltage, I is the current and R is the resistance. In this problem, the current is I=2 A, the voltage is V=120 V, therefore we can arrange the previous equation and find the resistance:

R=\frac{V}{I}=\frac{120 V}{2 A}=60 \Omega

7 0
2 years ago
A swimmer is swimming to the left with a speed of 1.0 m/s when she starts to speed up with constant acceleration. The swimmer re
kolezko [41]

Answer:

Correct answer: t = 2.86 seconds

Explanation:

We first use this formula

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We will calculate the acceleration from this formula

a = (V² - V₀²) / (2 d) = (2.5² - 1²) / (2 · 5) = (6.25 - 1) / 10 = 5.25 / 10

a = 0.525 m/s²

then we use this formula

V = V₀ + a t  => t = (V - V₀) / a = (2.5 - 1) / 0.525 = 1.5 / 0.525 = 2.86 seconds

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God is with you!!!

6 0
3 years ago
A satellite orbits a planet of unknown mass in a circular orbit of radius 2.3 x 104 km. The gravitational force on the satellite
sladkih [1.3K]

Answer:

The  kinetic energy is KE  =  7.59  *10^{10} \  J

Explanation:

From the question we are told that

       The  radius of the orbit is  r =  2.3 *10^{4} \ km  = 2.3  *10^{7} \ m

       The gravitational force is  F_g  = 6600 \ N

The kinetic energy of the satellite is mathematically represented as

       KE  =  \frac{1}{2} * mv^2

where v is the speed of the satellite which is mathematically represented as

     v  = \sqrt{\frac{G  M}{r^2} }

=>  v^2  =  \frac{GM }{r}

substituting this into the equation

      KE  =  \frac{ 1}{2} *\frac{GMm}{r}

Now the gravitational force of the planet is mathematically represented as

      F_g  = \frac{GMm}{r^2}

Where M is the mass of the planet and  m is the mass of the satellite

 Now looking at the formula for KE we see that we can represent it as

     KE  =  \frac{ 1}{2} *[\frac{GMm}{r^2}] * r

=>    KE  =  \frac{ 1}{2} *F_g * r

substituting values

       KE  =  \frac{ 1}{2} *6600 * 2.3*10^{7}

         KE  =  7.59  *10^{10} \  J

 

7 0
3 years ago
Una ola oceánica viaja a aproximadamente 1,97 m / s. Esto es 4 millas por hora. La frecuencia de las ondas es de aproximadamente
yKpoI14uk [10]

Answer:

λ = 28,14 m

Explanation:

To find the wavelength of the wave you use the following formula:

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You replace the values of v and f in the equation (1) and solve for λ:

\lambda=\frac{v}{f}=\frac{1,97m/s}{0,07Hz}=28,14m

hence, the wavelength of the wave is 28,14 m

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3 years ago
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