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jek_recluse [69]
3 years ago
15

What happens to light when it changes speed?

Physics
1 answer:
Brut [27]3 years ago
5 0
Hey there!

When light changes speed, it REFRACTS.
Your answer is going to be option C.

Hope this helps you.
Have a great day!
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Two blocks of masses M and 2M are initially traveling at the same speed v but in the opposite directions. They collide and stick
Hatshy [7]

Answer:

Explanation:

Given

Two masses M and 2 M with velocity v in opposite direction

After collision they stick together

Initial momentum

P_i=Mv-2Mv

final momentum

P_f=3Mv'

Conserving momentum

P_i=P_f

-Mv=3Mv'

v'=\frac{v}{3}

i.e. system moves towards the direction of 2M mass

Initial kinetic Energy K_1=\frac{1}{2}Mv^2+\frac{1}{2}2Mv^2

K_1=\frac{3}{2}Mv^2

Final Kinetic Energy K_2=\frac{1}{2}\cdot (3M)\cdot (\frac{v}{3})^2=\frac{3}{18}Mv^2

loss of Energy=K_1-K_2

=\frac{3}{2}Mv^2-\frac{3}{18}Mv^2

=\frac{4}{3}Mv^2

                   

3 0
3 years ago
Which trail is it? Answer!
Pepsi [2]
Wouldn’t it be 1. resistance is high compared to the voltage and with less resistance, higher current
4 0
3 years ago
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Challenge Problem (Extra Credit) A car with bad shocks has a mass of 1500 kg. Before you go for a drive with three of your frien
Nastasia [14]

Answer:

167.354 m

Explanation:

We are given;

The mass of the car with bad shock;

m = 1500 kg

The distance at which the car sinks; x =

6 cm = 6 × 10^(−2) m

The total mass of 4 people; m_t = 11 kg

The total speed in the highway; V = 65

mph = 29.058 m/s

The spring's constant can be calculated from the formula;

F = Kx

F is also equal to mg.

Thus;

m_t × g = Kx

K = (m_t × g)/x

K = (11 × 9.81)/(6 × 10^(−2))

K = 1798.5 N/m

Mass of car and four people;m_(c+t) = 1500 + 11 = 1511 kg

Thus, the period cam be calculated from the formula;

T = 2π√((m_c+t)/k)

T = 2π√(1511/1798.5)

T = 5.759 s

the distance between adjacent bumps is calculated from;

Velocity = distance/time

Distance = velocity x time

Distance = 29.058 × 5.759

Distance = 167.354 m

4 0
4 years ago
A flat, circular, copper loop of radius r is at rest in a uniform magnetic field of magnitude B that extends far beyond the edge
GarryVolchara [31]

Answer:

     i =- \frac{r \ A'}{2 \ rho} ,  i =  0.92   A

Explanation:

This exercise asks for the electromotive force, which can be calculated with Faraday's law

          fem = - \frac{d \Phi_B }{dt}

where the magnetic flux

          Ф = B. A

bold letters indicate vectors. We can write this equation

          Ф = B A cos θ

In this case the magnetic field is perpendicular to the page and the normal to the loop of the loop is also parallel to the page, therefore the angle is zero and the cosine is 1

the loop is

          A = π r²

we substitute in the first equation

          fem = - π r² \frac{dB}{dt}

we substitute the values

          fem = -π r² 1

          fem = - π r²

to calculate the current let's use ohm's law

           V = i R

            R = ρ L / A'

where A 'is the area of ​​the wire and L is the length of the loop

            L = 2π r

           

            V = i (ρ 2π r / A ')

            I = \frac{V \ A'}{2\pi  \ r  \ rho}

         

In this case

           V = fem

 

           I = fem / R            

           i =- \frac{r \ A'}{2 \ rho}

         

In order to complete the calculation, you need the radius of the loop and / or the wire cutter.

if we assume that the loop has a radius of r = 1 cm = 0.01 m and an area of ​​the wire   A'= π 10⁻⁶ m²   a radius of the wire 1 mm

           i = - 10⁻² π 10⁻⁶ / ( 2 1.7 10-8)

           i =  0.92   A

5 0
3 years ago
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tamaranim1 [39]
Photoelectric effect
4 0
4 years ago
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