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2 years ago

Which of the following has greater kinetic energy?

Physics

1 answer:

uysha [10]2 years ago

5 0

I aint got no clue ask someone that knows about this.

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Why are chemical changes considered "unseen"

morpeh [17]

Because they occur at an atomic level, changing the actual structure of the thing.
Hope it helps

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3 years ago

If a boy with 50kg run in 3m/s what is his velocity

stepladder [879]

His velocity is 3 m/s in the direction in which he is running in. which.

6 0

3 years ago

Read 2 more answers

g Estimate the number of photons emitted by the Sun in a second. The power output from the Sun is 4 Ã— 1026 W and assume that th

vagabundo [1.1K]

Answer:

The value is $N = 1.107 *10^{45 } \ photons$

Explanation:

From the question we are told that

The power output from the sun is $P_o = 4 * 10^{26} \ W$

The average wavelength of each photon is $\lambda = 550 \ nm = 550 *10^{-9} \ m$

Generally the energy of each photon emitted is mathematically represented as

$E_c = \frac{h * c }{ \lambda }$

Here h is the Plank's constant with value $h = 6.62607015 * 10^{-34} J \cdot s$

c is the speed of light with value $c = 3.0 *10^{8} \ m/s$

$E_c = \frac{6.62607015 * 10^{-34} * 3.0 *10^{8} }{ 550 *10^{-9} }$

=> $E_c = 3.614 *10^{-19} \ J$

Generally the number of photons emitted by the Sun in a second is mathematically represented as

$N = \frac{P }{E_c}$

=> $N = \frac{4 * 10^{26} }{3.614 *10^{-19}}$

=> $N = 1.107 *10^{45 } \ photons$

5 0

2 years ago

In what direction does the induced current flow in the loop?

bogdanovich [222]

Answer:

Clockwise and counter clockwises, depands.

Explanation:

The direction of current in a loop of wire in a magnatic field depands on the direction in which the loop is moved and the applied magnatic field.

this is determined by what is called right hand rule.

I will give one scenario, let's say that the loop is moved upwards and the applied magnatic field is into the page (if you drew the loop in 2D on a piece of paper), in this case the direction would be clockwise.

6 0

3 years ago

Without the wheels, a bicycle frame has a mass of 6.71 kg. Each of the wheels can be roughly modeled as a uniform solid disk wit

dalvyx [7]

Answer:43.311 J

Explanation:

Given

mass of frame $\left ( m_f\right )=6.71 kg$

mass of wheel $\left ( m_w\right )=0.820 kg$

radius of wheel $\left ( r\right )=0.343 m$

v=3.22 m/s

Moment of inertia of each wheel\left ( I\right )=\frac{1}{2}mr^2[/tex]

$I=0.0482 kg-m^2$

kinetic Energy of whole cycle=Kinetic energy of wheels and frame+rotational energy of Wheels

$K.E.=\frac{1}{2}\left ( m_f+m_w\right )v^2+2\times \frac{1}{2}I\omega ^2$

$K.E.=\frac{1}{2}\left ( 6.71+0.820\right )3.22^2+2\times \frac{1}{2}0.0482\times \left ( \frac{3.22}{0.343}\right )^2$

K.E.=39.037+4.274=43.311J

4 0

3 years ago