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mestny [16]
3 years ago
12

45.761 g - 42.98 = ___________

Chemistry
2 answers:
almond37 [142]3 years ago
5 0

I believe your answer would be

2.781

Alja [10]3 years ago
4 0
The correct answer is 2,781
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Explain the hypothesis that eukaryotes evolved from prokaryotes.
snow_lady [41]

Answer:

The hypothesis that eukaryotic cells evolved from a symbiotic association of prokaryotes—endosymbiosis—is particularly well supported by studies of mitochondria and chloroplasts, which are thought to have evolved from bacteria living in large cells.

Explanation:  Both mitochondria and chloroplasts are similar to bacteria in size, and like bacteria, they reproduce by dividing in two. Most important, both mitochondria and chloroplasts contain their own DNA, which encodes some of their components. The mitochondrial and chloroplast DNAs are replicated each time the organelle divides, and the genes they encode are transcribed within the organelle and translated on organelle ribosomes. Mitochondria and chloroplasts thus contain their own genetic systems, which are distinct from the nuclear genome of the cell. Furthermore, the ribosomes and ribosomal RNAs of these organelles are more closely related to those of bacteria than to those encoded by the nuclear genomes of eukaryotes.

4 0
4 years ago
In the solubility lab, sugar was the _____________ and water was the _______________.
Rasek [7]

In a homogenous mixture, sugar was the solute and water was the solvent. Solubility is the maximum amount of a solute that dissolves in a given amount of solvent at a constant temperature. Solutes are more soluble in a given solvent at higher temperatures. Therefore, when temperature increases, the solubility of the solute also increases.

<span>Moreover, the solubility of the substance ranges from infinitely soluble such as alcohol in water, to poorly soluble like silver chloride in water and the species that dissolves, the solute, can be another liquid, gas or a solid.</span>

4 0
3 years ago
Solutions of mercury (I) nitrate and potassium bromide are mixed
Afina-wow [57]
With that informatio you can:

1) Write the chemical equation
2) Balance the chemical equation
3) State the molar ratios
4) Predict if precipitation occurs.

I will do all four, for you:

1) Chemical equation:

mercury(I) nitrate  potassium bromide    mercury(I) bromide  potassium nitrate
<span>Hg2(NO3)2             +        KBr                   → Hg2Br2          +      KNO<span>3

2) Balanced chemical equation
</span></span>
<span>Hg2(NO3)2 + 2KBr → Hg2Br2 + 2KNO<span>3

3) Molar ratios or proportions:

1 mol </span></span><span>Hg2(NO3)2 : 2 mol KBr : 1 mol Hg2Br2 : 2 mol KNO<span>3

4) Prediction of precipitation.

You can use the solubility rules or a table of solubilities. I found in a table of solutiblities that mercury(I) bromide is insoluble and potassium bromide is soluble, Then you can predict that the precipitation of mercury(I) bromide will occur.


</span></span>
7 0
3 years ago
When the u-235 nucleus is struck with a neutron, the ce-144 and sr-90 nuclei are produced, along with some neutrons and beta par
butalik [34]
Answer: 2 (2 neutrons are produced).

Explanation:

1) In the left side of the transmutation equationa appears:
²³⁵U + ¹n →

I am omitting the atomic number (subscript to the leff) because the question does not show them as it is focused on number of neutrons.


2) The right side of the transmutation equation has:

→ ¹⁴⁴Ce + ⁹⁰Sr + ?

3) The total mass number of the left side is 235 + 1 = 236

4) The total mass number of Ce and Sr on the right side is 144 + 90 = 234

5) Then, you are lacking 236 - 234 = 2 unit masses on the right side which are the 2 neutrons that are produced along with the Ce and Sr.

The complete final equation is:

²³⁵U + ¹n → ¹⁴⁴Ce + ⁹⁰Sr + 2 ¹n

Where you have the two neutrons produced.
6 0
4 years ago
Plz help, I will give brainliest.
baherus [9]

Answer: The value of K_c is 2

Explanation:

Moles of  N_2O_4 = 1.0 mole  

Volume of solution = 1.00 L

Initial concentration of N_2O_4 = \frac{1.0mol}{1.00L}=1.0M

Equilibrium concentration of NO_2 = \frac{1.0mol}{1.00L}=1.0M  

The given balanced equilibrium reaction is,

                            N_2O_4(g)\rightleftharpoons 2NO_2(g)

Initial conc.          1.0 M            0 M

At eqm. conc.     (1.0-x) M      (2x) M

The expression for equilibrium constant for this reaction will be,

K_c=\frac{[NO_2]^2}{[N_2O_4]}

Given : 2x = 1.0

x= 0.5

Now put all the given values in this expression, we get :

K_c=\frac{(1.0)^2}{(1.0-0.5)}

K_c=2

Thus the value of K_c is 2

4 0
3 years ago
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