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Illusion [34]
3 years ago
10

The two elements discovered by Marie Curie are _____ and _____. uranium curium radium polonium

Chemistry
2 answers:
denpristay [2]3 years ago
5 0
Marie Curie discovered polonium and radium. Hope this helps:))) Please, mark Brainliest!
Savatey [412]3 years ago
3 0
Marie Curie discovered polonium and Radium.
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Why is an extraction a useful method of "pre-purification" of organic compounds? what physical properties does the process rely
ASHA 777 [7]

Explanation :

Extraction : It is a separation technique in which one compound is separated from a mixture of compounds.

In  a chemical process, the solution may not contain only the desired product but there maybe a mixture of products present.

So, for obtaining the desired product we need to get rid of the other products in a mixture like catalyst (if used), other by products or unreacted starting material.

For a compound to be extracted it has to be soluble in the extracting solvent.

Therefore, this process is based on the miscibility of solute and solvent in a mixture.



7 0
3 years ago
Read 2 more answers
Consider the molecules H2O, H2S, H2Se, and H2Te. Which do you expect to have the highest boiling point, and why?
STatiana [176]

Answer:

a. H20,because it experiences hydrogen bonding.

5 0
3 years ago
I need help on this right now it is due it 12mins please help!!!
Maurinko [17]

Where is the work (I'll edit the answer)

6 0
3 years ago
Write the electron configuration for the following elements. (1) Neon, (2) Zinc, (3) Tungsten, (4) Magnesium
mash [69]

Explanation:

Hey there!!

We generally use s,p,d,f formula.

So, let's do with it.

1.Neon

Atomic no. = 10

So, Its electronic configuration is;

= 1  {s}^{2} .2 {s}^{2} 2 {p}^{6}

2.Zinc.

Atomic no. = 30

So, it's electronic configuration is;

= 1 {s}^{2} 2 {s}^{2} 2 {p}^{6} 3 {s}^{2} 3 {p}^{6} 4 {s}^{2} 3 {d}^{10}

3. Tungsten.

Atomic no. = 74.

So, it's electronic configuration is;

= 1 {s}^{2} 2 {s}^{2} 2 {p}^{6} 3 {s}^{2} 3 {p}^{6} 4 {s}^{2} 3 {d}^{10}4 {p}^{6} 5 {s}^{2} 4 {d}^{10} 5 {p}^{6} 6 {s}^{2} 4 {f}^{14} 5 {d}^{4}

4. Magnesium.

Atomic no. = 12

So, the electronic configuration is ;

= 1 {s}^{2} 2 {s}^{2} 2 {p}^{6}3 {s}^{2}

<em><u>Hope it helps</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>

3 0
4 years ago
How many grams of Na2SO4, (molar mass =142.0 g/mol) are there in 15 mL of 0.50 m Na2SO4 solution?
ElenaW [278]

Answer:

1.1 g Na2SO4

Explanation:

First convert mL to L. Then multiply by the Molarity to get moles, then multiply by the molar mass to get grams.

15 mL x     1 L       x       0.50 mol Na2SO4     x        142 g        =          1.1 g

              10^3 mL                 1 L                                   mol                     Na2SO4

3 0
3 years ago
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