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irga5000 [103]
2 years ago
8

Karl likes to use cruise control when he drives on

Chemistry
1 answer:
Yanka [14]2 years ago
3 0

Answer:

3.96 MINUTES

Explanation:

Karl likes to use cruise control when he drives on

the highway. After setting cruise control at 33.53

m/s (75 mph). At this speed, how long would it

take Karl to travel 8 kilometers?

VELOCITY = DISTANCE/TIME

OR

V=D/T

SO

VT=D

SO

T=D/V

THE DISTANCE IS 8 KM

THE VELOCITY IS 75 MPH

THERE ARE 1.61 KM PER MILE

SO

75M[H =

75 X 1.61 KM/H =

121 KM/HR

T=D/V

T=8/121 =0.066 HOUR =

0.066 X 60 MINUTES =

3.96 MINUTES

CHECK

75 MPH =

(75 X 1.61) KM/60 MINUTES =

120,75 KM/60 MINUTES=

2.01 KM/MINUTE

to travel 8 K,M WILL TAKE

8/2.01 = 3.98 minutes

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A sample of iron is put into a calorimeter (see sketch at right) that contains of water. The iron sample starts off at and the t
Mariulka [41]

Answer:

Therefore, the specific heat capacity of the iron is 0.567J/g.°C.

<em>Note: The question is incomplete. The complete question is given as follows:</em>

<em>A 59.1 g sample of iron is put into a calorimeter (see sketch attached) that contains 100.0 g of water. The iron sample starts off at 85.0 °C and the temperature of the water starts off at 23.0 °C. When the temperature of the water stops changing it's 27.6 °C. The pressure remains constant at 1 atm. </em>

<em> Calculate the specific heat capacity of iron according to this experiment. Be sure your answer is rounded to the correct number of significant digits</em>

Explanation:

Using the formula of heat, Q = mc∆T  

where Q = heat energy (Joules, J), m = mass of a substance (g)

c = specific heat capacity (J/g∙°C), ∆T = change in temperature (°C)

When the hot iron is placed in the water, the temperature of the iron and water attains equilibrium when the temperature stops changing at 27.6 °C. Since it is assumed that heat exchange occurs only between the iron metal and water; Heat lost by Iron = Heat gained by water

mass of iron  = 59.1 g, c = ?, Tinitial = 85.0 °C, Tfinal = 27.6 °C

∆T = 85.0 °C - 27.6 °C = 57.4 °C

mass of water = 100.0 g, c = 4.184 J/g∙°C, Tinitial = 23.0 °C, Tfinal = 27.6 °C

∆T = 27.6°C - 23.0°C = 4.6 °C

Substituting the values above in the equation; Heat lost by Iron = Heat gained by water

59.1 g * c * 57.4 °C  = 100.0 g * 4.184 J/g.°C * 4.6 °C

c = 0.567 J/g.°C

Therefore, the specific heat capacity of the iron is 0.567 J/g.°C.

5 0
2 years ago
Standard reduction potentials for nickel(II) and copper(II) The standard reduction potential for a substance indicates how readi
AleksandrR [38]

Answer:

The standard potential, E cell, for this galvanic cell is 0.5670V

Explanation:

Ni²⁺(aq)  +  2e⁻   →   Ni(s)           E red =  - 0.23V      ANODE

Cu²⁺(aq) +  2e-    →  Cu(s)          E red = + 0.337V    CATHODE

ΔE° = E cathode - E anode

ΔE° = 0.337V - (0.23V) = 0.5670 V

6 0
2 years ago
Is water used to test cheese for protein
nekit [7.7K]

Answer:

yes

Explanation:

because it help the body hydrate

7 0
2 years ago
What is the mass of 0.042 mole C8H18
stiks02 [169]

Hope this help you!!! :))

4 0
3 years ago
Calculate the pOH of a solution that contains 3.9 x 10-5 M H3O+ at 25°C.
exis [7]

Answer:

Option b. 9.59

Explanation:

First, let us calculate the pH. This is illustrated below:

[H3O+] = 3.9 x 10-5 M

pH = —Log [H3O+]

pH = —Log [3.9 x 10-5]

pH = 4.41

Recall: pH + pOH = 14

4.41 + pOH = 14

Collect like terms

pOH = 14 — 4.41

pOH = 9.59

6 0
3 years ago
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