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Fantom [35]
3 years ago
15

What is the heat of vaporization of nitrous oxide in kJ/mol?

Chemistry
1 answer:
Juli2301 [7.4K]3 years ago
3 0

Answer:

The standard heat of vaporization of nitrous oxide is 16.5 kJ/mol

Explanation:

The standard heat of vaporization \mathbf{\Delta H^{\theta}_{vap}} , occurs as the result of a change in heat when 1 mole of a liquid is vaporized. The standard heat of vaporization is always positive i.e endothermic. In the given question, we are asked to determine what the standard heat of vaporization of nitrous oxide.

i.e

\mathbf{N_2O_{(l)} \to N_2O_{(g)} \ \ \ \Delta H^{\theta}_{vap} = +16.5 \ kJ/mol}

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Tire manufacturers design tires to stop quickly in various conditions. Use the table to answer the question: Which tire would be
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Can you show the picture?


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3 years ago
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A container is filled to a volume of 55.2 L at 61 °C. While keeping the
babymother [125]

Answer:

4.45 atm

Explanation:

Applying,

PV = P'V'............ Equation 1

Where P = Initial pressure of the container, V = Initial volume of the container, P' = Final pressure of the container, V' = Final volume of the container.

make P the subject of the equation

P = P'V'/V........... Equation 2

From the question,

Given: V = 55.2 L, P' = 8.53 atm, V' = 28.8 L

Substitute these values into equation 2

P = (8.53×28.8)/55.2

P = 4.45 atm

5 0
3 years ago
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Whats the name of CaS?
sergejj [24]

Answer

Chemical formula or Chemical Abstracts Service

Explanation:

A CAS (Chemical Abstracts Service) Registry Number is a unique identifier that tells you, for example, that acetone and dimethyl ketone are actually the same substance.

4 0
3 years ago
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What is the pressure of a fixed volume of hydrogen gas at 38.8°C if it has a pressure of 1.36 atm at 15.0°C?
Rainbow [258]
Hello There! ^_^

Your question: What is the pressure of a fixed volume of hydrogen gas at 38.8°C if it has a pressure of 1.36 atm at 15.0°C..?

Your answer: P1/ T1= P2/ T2
                    
                     Change C to Kelvin
   
                     273+ C= K
               
                     38.3+ 273= 311K
                      
                      15.0+ 273= 288K
                       
                       2.38/ 288= P2/ 311.3
                          
                        740.894= 288 (P2)
                        
                         P2= 2.57 atm.


 Thus, you got you answer!

  Hope this helps!





  

       



    

 

  






4 0
3 years ago
El osmio es un metal sólido que tiene una densidad
pentagon [3]

Respuesta:

4.42 × 10⁻⁶ m³

Explicación:

Paso 1: Información provista

  • Densidad del osmio (ρ): 22600 kg/m³
  • Masa de osmio (m): 100 g

Paso 2: Convertir 100 g a kilogramos

Usaremos el factor de conversion 1 kg = 1000 g.

100 g × 1 kg/1000 g = 0.100 kg

Paso 3: Calcular el volumen ocupado por 0.100 kg de osmio

La densidad es una propiedad intensiva, igual al cociente entre la masa y el volumen.

ρ = m/V

V = m/ρ

V = 0.100 kg / (22600 kg/m³) = 4.42 × 10⁻⁶ m³

5 0
3 years ago
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