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Aleksandr-060686 [28]
3 years ago
11

Can you guys pretty please help me with my science

Chemistry
2 answers:
morpeh [17]3 years ago
8 0
4.) C.summer

5.) A. new moon

6.) A. One

andreyandreev [35.5K]3 years ago
7 0

C) Summer

B) Full Moon

A) One (look up a lunar calendar, those can help with these question)

Hope this helps you :)

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Question 19-20<br> I’m not really sure, can someone help me
Nesterboy [21]
Hi my name is Jaleesa The answer = -1
6 0
3 years ago
Acetone is a common solvent that has a density of 0.7899 g/mL. What volume of acetone, in milliliters, has a mass of 44.2 g
balu736 [363]

The volume of acetone, in milliliters, has a mass of 44.2 g is 55.96mL.

<h3>HOW TO CALCULATE VOLUME?</h3>

The volume of a substance can be calculated by dividing the mass by its density. That is;

Volume (mL) = mass (g) ÷ density (g/mL)

According to this question, acetone is a solvent with density of 0.7899g/mL and mass of 44.2g. The volume is calculated as follows:

Volume = 44.2g ÷ 0.7899g/mL

Volume = 55.96mL

Therefore, the volume of acetone, in milliliters, has a mass of 44.2g is 55.96mL.

Learn more about volume at: brainly.com/question/1578538

5 0
3 years ago
State what happens to atoms in a chemical reaction
Blababa [14]
The outermost electrons of the atom are either lost or gained by one of the atoms to the other. therefore the atom gains negative charge when gaining and positive charge when losing
6 0
3 years ago
) Predict the product for the following reaction sequence. A) 2,2-dimethylpropanoic acid B) 3,3-dimethyl-2-butanone C) 2,2-dimet
cestrela7 [59]

Answer:

Option C. 2,2-dimethyl-1-propanol

Explanation:

The first attached picture, is the initial reactant.

Now, what happens in each step?, at first we have an alkyl bromide reacting with Mg/ether. This converts the reactant in a grignard reagent, which is often used in several ketones/ladehydes reactions, and even some acid and esthers.

Now, in the second step, we see this grignard reagent, reacting with CO₂ and H₃O⁺. At first, the grignard reagent will attach to the oxygen of the CO₂ by the MgBr, and the carbonated chain will attach to the carbonile. Then in acid medium, the OMGBr leaves the molecule, and form a carboxylic acid.

Finally, in the last step with LiAlH₄ and water, this compound just reduces the carboxylic acid to a primary alcohol, therefore, the only choice available is option c, 2,2-dimethyl-1-propanol.

See picture 2 below for the drawing.

Hope this helps

8 0
3 years ago
Given the following balanced equation at 120°C: A(g) + B(g) ⇋ 2 C(g) + D(s)(a) At equilibrium a 4.0 liter container was found to
BlackZzzverrR [31]

Answer:

a) kc = 0,25

b) [A] = 0,41 M

c) [A] = <em>0,8 M</em>

[B] =<em>0,2 M</em>

[C] = <em>0,2M</em>

Explanation:

The equilibrium-constant expression is defined as the ratio of the concentration of products over concentration of reactants. Each concentration is raised to the power of their coefficient.

Also, pure solid and liquids are not included in the equilibrium-constant expression because they don't affect the concentration of chemicals in the equilibrium.

If global reaction is:

A(g) + B(g) ⇋ 2 C(g) + D(s)

The kc = \frac{[C]^2}{[A][B]}

a) The concentrations of each compound are:

[A] = \frac{1,60 moles}{4,0 L} = <em>0,4 M</em>

[B] = \frac{0,40 moles}{4,0 L} = <em>0,1 M</em>

[C] = \frac{0,40 moles}{4,0 L} = <em>0,1 M</em>

<em>kc = </em>\frac{[0,1]^2}{[0,4][0,1]} = 0,25

b) The addition of B and D in the same amount will, in equilibrium, produce these changes:

[A] = \frac{1,60-x moles}{4,0 L}

[B] = \frac{0,60-x moles}{4,0 L}

[C] = \frac{0,60+2x moles}{4,0 L}

0,25 = \frac{[0,60+2x]^2}{[1,60-x][0,60-x]}

You will obtain

3,75x² +2,95x +0,12 = 0

Solving

x =-0,74363479081119   → No physical sense

x =-0,043031875855476

Thus, concentration of A is:

\frac{1,60-(-0,04 moles)}{4,0 L} = <em>0,41 M</em>

c) When volume is suddenly halved concentrations will be the concentrations in equilibrium over 2L:

[A] = \frac{1,60 moles}{2,0 L} = <em>0,8 M</em>

[B] = \frac{0,40 moles}{2,0 L} = <em>0,2 M</em>

[C] = \frac{0,40 moles}{2,0 L} = <em>0,2M</em>

I hope it helps!

8 0
4 years ago
Read 2 more answers
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