F=ma so a=F/m
a=225/55=4.09 m/sec^2
Answer: 0.258 N
Explanation:
As the density of the object is much less than the density of water, it’s clear that the buoyant force, is greater than the weight of the object, which means that in normal conditions, it would float in water.
So, in order to get the ball submerged in water, we need to add a downward force, that add to the weight, in order to compensate the buoyant force, as follows:
F = Fb – Fg
Fb= δH20* 4/3*π*(d/2)³ * g
Fg = δb* 4/3*π*(d/2)³ *g
F= (δH20- δb) * 4/3*π*(d/2)³*g
Replacing by the values of the densities, and the ball diameter, we finally get:
F= 0.258 N
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Answer:
a)
b)N= 21.29 rpm
Explanation:
Given that
Mass of the ball =m
Length of string = L
Lets take angular speed = ω
The centripetal force on the ball
F = m ω² L
To complete the circle ,at the top condition the force due to gravity should be equal to the centripetal force
Gravity force = mg
F= mg
m ω² L = m g
ω² L = g

When L= 2 m
Lets take g =10 m/s²


ω = 2.23 rad/s
To convert in rpm

N=Speed in rpm

N= 21.29 rpm
Answer:
4.9 m/s
Explanation:
Since the motion of the ball is a uniformly accelerated motion (constant acceleration), we can solve the problem by using the following suvat equation:

where
v is the final velocity
u is the initial velocity
a is the acceleration
s is the distance covered
For the ball in this problem,
u = 0 (it starts from rest)
is the acceleration
s = 3 m is the distance covered
Solving for v,
