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4 years ago

A ball having a mass of 500 grams is dropped from a height of

2 answers:

5 0

M*g*h
where m = mass, g = acceleration due to gravity (9.8 m/s^2), h = height
Given m = 500g = 0.5 kg, h = 9 meters
0.5*9*9.8 = 44.1 joules

Levart [38]4 years ago

4 0

Answer:

(9.8 m/s^2), h = height

Given m = 500g = 0.5 kg, h = 9 meters

0.5*9*9.8 = 44.1 joules

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If a body travels half its total path in the last 1.50 s of its fall from rest, find the total time of its fall (in seconds).

svetoff [14.1K]

Answer:

time to fall is 3.914 seconds

Explanation:

given data

half distance time = 1.50 s

to find out

find the total time of its fall

solution

we consider here s is total distance

so equation of motion for distance

s = ut + 0.5 × at² .........1

here s is distance and u is initial speed that is 0 and a is acceleration due to gravity = 9.8 and t is time

so for last 1.5 sec distance is 0.5 of its distance so equation will be

0.5 s = 0 + 0.5 × (9.8) × ( t - 1.5)² ........................1

and

velocity will be

v = u + at

so velocity v = 0+ 9.8(t-1.5) ..................2

so first we find time

0.5 × (9.8) × ( t - 1.5)² = 9.8(t-1.5) + 0.5 ( 9.8)

solve and we get t

t = 3.37 s

so time to fall is 3.914 seconds

6 0

4 years ago

The coefficient of the restitution of an object is defined as the ratio of its outgoing to incoming speed when the object collid

IgorLugansk [536]

Answer:

48.16 %

Explanation:

coefficient of restitution = 0.72

let the incoming speed be = u

let the outgoing speed be = v

kinetic energy = 0.5 x mass x $x velocity^{2}$

incoming kinetic energy = 0.5 x m x $x u^{2}$

coefficient of restitution = $\frac{v}{u}$

0.72 = $\frac{v}{u}$

v = 0.72u

therefore the outgoing kinetic energy = 0.5 x m x $(0.72u)^{2}$

outgoing kinetic energy = 0.5 x m x $0.5184 x u^{2}$

outgoing kinetic energy = 0.5184 (0.5 x m x $x u^{2}$ )

recall that 0.5 x m x $x u^{2}$ is our incoming kinetic energy, therefore

outgoing kinetic energy = 0.5184 x (incoming kinetic energy)

from the above we can see that the outgoing kinetic energy is 51.84 % of the incoming kinetic energy.

The energy lost would be 100 - 51.84 = 48.16 %

5 0

3 years ago

Suppose we could shrink the earth without changing its mass..?At what fraction of its current radius would the free-fall acceler

Drupady [299]

Answer:

at R/ $\sqrt{3}$

Explanation:

The free-fall acceleration at the surface of Earth is given by

$g=\frac{GM}{R^2}$

where

G is the gravitational constant

M is the Earth's mass

R is the Earth's radius

The formula can be rewritten as

$R=\sqrt{\frac{GM}{g}}$ (1)

We want to shrink the Earth at a radius R' such that the acceleration of gravity becomes 3 times the present value, so

g' = 3g

Keeping the mass constant, M, and substituting into the equation, we have

$3g=\frac{GM}{R'^2}$

$R'=\sqrt{\frac{GM}{3g}}=\frac{1}{\sqrt{3}}\sqrt{\frac{GM}{g}}=\frac{R}{\sqrt{3}}$

5 0

3 years ago

Read 2 more answers

Electric devices use electric _____ to function

Rina8888 [55]

AC or DC

someone use active current or Direct current

6 0

3 years ago

(15 points)

vodomira [7]

Answer:

1. Decrease

2. Decrease

3. Stay the same

Explanation:

1. The more predators there are that eat the prey(cricket/frog), the less prey there will be.

2. The more the pollution effects them negatively, the more the population will die off.

3. The decrease of food may kill the population, but the increase of food does not effect the birth rate of the population.

4 0

3 years ago