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Zielflug [23.3K]
4 years ago
12

A ball having a mass of 500 grams is dropped from a height of

Physics
2 answers:
oee [108]4 years ago
5 0
M*g*h
where m = mass, g = acceleration due to gravity (9.8 m/s^2), h = height
Given m = 500g = 0.5 kg, h = 9 meters
0.5*9*9.8 = 44.1 joules
Levart [38]4 years ago
4 0

Answer:

(9.8 m/s^2), h = height

Given m = 500g = 0.5 kg, h = 9 meters

0.5*9*9.8 = 44.1 joules

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1. What is evaporation and how does it affect weather?
alina1380 [7]

Answer:

Explanation:don’t know

8 0
3 years ago
Energy is to be stored in a flywheel in the shape of a uniform solid disk with a radius of R = 1.22 m and a mass of 67.0 kg . To
eduard

Answer: 71.7 KJ

Explanation:

The rotational kinetic energy of a rotating body can be written as follows:

Krot = ½ I ω2

Now, any point on the rim of the flywheel, is acted by a centripetal force, according to Newton’s 2nd Law, as follows:

Fc = m. ac

It can be showed that the centripetal acceleration, is related with the angular velocity and the radius, as follows:

ac =  ω2 r

We know that this acceleration has a limit value, so , we can take this limit to obtain a maximum value for the angular velocity also.

As the flywheel is a solid disk, the rotational inertia I is just ½ m r2.

Replacing in the expression for the Krot, we have:

Krot= ½ (1/2 mr2.ac/r) = ¼ mr ac = ¼ 67.0 Kg. 1.22 m . 3,510 m/s2 = 71. 7 KJ

5 0
3 years ago
In an inkjet printer, letters and images are created by squirting drops of ink horizontally at a sheet of paper from a rapidly m
Serga [27]

Answer:

q = 6.48 \times 10^{-14} C

Explanation:

Deflection in the drop is due to electric field force

so we will have

F = qE

acceleration of the drop is given as

a = \frac{qE}{m}

a = \frac{q(7.75 \times 10^4)}{1.00 \times 10^{-11}}

a = 7.75 \times 10^{15} q

now we know that time to cross the plates is given as

t = \frac{D}{v}

t = \frac{0.02}{18}

t = 1.11 \times 10^{-3} s

now the deflection is given as

d = \frac{1}{2}at^2

0.310 \times 10^{-3} = \frac{1}{2}(7.75 \times 10^{15} q)(1.11 \times 10^{-3})^2

0.310 \times 10^{-3} = 4.78 \times 10^9 q

q = 6.48 \times 10^{-14} C

5 0
3 years ago
A simple pendulum is made by tying a 2.44 kg stone to a string 4.57 m long. The stone is projected perpendicularly to the string
alexdok [17]

Answer:

v_{max}=8.2226m/s

Explanation:

The problem is solved using the law of conservation of energy,

So

mgL(1-cos\theta)+\frac{1}{2}mv^2_0=\frac{1}{2}mv^2_{max}

v_{max}=\sqrt{2gL(1-cos\theta)+v^2_0}

v_{max}=\sqrt{2(9.8)(4.57)(1-cos(69.4))+8^2}

v_{max}=8.2226m/s

8 0
3 years ago
A train travels 79 kilometers in 2 hours, and then 77 kilometers in 3 hours. What is its average speed?
koban [17]
Average speed=total distance traveled/time. Total distance=the sum of the two short distances=79*2+77*3=389 km. Total time used to travel is 2+3=5 hr. Average speed is 389/5=77.8 km/hr.
4 0
3 years ago
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