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3 years ago

Please answer this correctly

Mathematics

2 answers:

kvv77 [185]3 years ago

3 0

Answer:

New mean will be( 8 + 3 + 4 + 2 + 8) / 2

= 25/5 = 5 (old was 6)

New median will be 4 (old was 8)

-Dominant- [34]3 years ago

3 0

Answer:

Mean, Mean would change the most the original mean was 28.4, after replacing 9 with 4 it changed to 23.4. With the difference of 5.

Step-by-step explanation:

Mode will stay the same with the repetition of 8, median will be a 4 difference from 8 to 4

You might be interested in

A certain pickup truck gets 20mpg in the city and 28 mpg on the highway. If the driver drives 270 mi on 11 gal of gas, determine

Snezhnost [94]

Answer:

95 city and 175 highway miles.

Step-by-step explanation:

The driver gets 20 mpg in city, and 28 mpg on the highway.

An equation that could be written is

20x+28y=270

This equation accounts for the distance traveled.

x+y=11

This equotion accounts for how many gallons were driven.

Multiply the bottom equation by 20, so you can solve the set of equations.

20x+28y=270

20x+20y=220

subtract them

8y=50

y=6.25

now plug this back into x+y=11

x+6.25=11

x=4.75

Now 4.75×20=95 city miles and 6.25×28=175 highway miles.

8 0

4 years ago

Part B please help me

Juliette [100K]

He drinks 0.75 liters of juice each day
or
6/8 liters of juice each day

8 0

3 years ago

Sales tax for an item was 13.80$ and it cost 460$ before tax. Whats the sale tax rate in percentage?

Butoxors [25]

It is $2837383 dollars

8 0

3 years ago

Read 2 more answers

. Use the quadratic formula to solve each quadratic real equation. Round

Liono4ka [1.6K]

Answer:

A. No real solution

B. 5 and -1.5

C. 5.5

Step-by-step explanation:

The quadratic formula is:

$\begin{array}{*{20}c} {\frac{{ - b \pm \sqrt {b^2 - 4ac} }}{{2a}}} \end{array}$ , with a being the x² term, b being the x term, and c being the constant.

Let's solve for a.

$\begin{array}{*{20}c} {\frac{{ 5 \pm \sqrt {5^2 - 4\cdot1\cdot11} }}{{2\cdot1}}} \end{array}$

$\begin{array}{*{20}c} {\frac{{ 5 \pm \sqrt {25 - 44} }}{{2}}} \end{array}$

$\begin{array}{*{20}c} {\frac{{ 5 \pm \sqrt {-19} }}{{2}}} \end{array}$

We can't take the square root of a negative number, so A has no real solution.

Let's do B now.

$\begin{array}{*{20}c} {\frac{{ 7 \pm \sqrt {7^2 - 4\cdot-2\cdot15} }}{{2\cdot-2}}} \end{array}$

$\begin{array}{*{20}c} {\frac{{ 7 \pm \sqrt {49 + 120} }}{{-4}}} \end{array}$

$\begin{array}{*{20}c} {\frac{{ 7 \pm \sqrt {169} }}{{-4}}} \end{array}$

$\begin{array}{*{20}c} {\frac{{ 7 \pm 13 }}{{-4}}} \end{array}$

$\frac{7+13}{4} = 5\\\frac{7-13}{4}=-1.5$

So B has two solutions of 5 and -1.5.

Now to C!

$\begin{array}{*{20}c} {\frac{{ -(-44) \pm \sqrt {-44^2 - 4\cdot4\cdot121} }}{{2\cdot4}}} \end{array}$

$\begin{array}{*{20}c} {\frac{{ 44 \pm \sqrt {1936 - 1936} }}{{8}}} \end{array}$

$\begin{array}{*{20}c} {\frac{{ 44 \pm 0}}{{8}}} \end{array}$

$\frac{44}{8} = 5.5$

So c has one solution: 5.5

Hope this helped (and I'm sorry I'm late!)

4 0

3 years ago

If P( A or B) = 2/5, P(B)=1/4 and <br> P( A and B) = 1/10 find P(A)

natulia [17]

Answer:

p(a) = -3/20

Step-by-step explanation:

p ( a +b) = p(a)+p(b)

1/10= p(a) +1/4

1/10 - 1/4 = p(a)

p(a) = -3/20

5 0

3 years ago