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jekas [21]
3 years ago
7

How many pairs are shared between the nitrogen atoms for hydrazine

Chemistry
1 answer:
morpeh [17]3 years ago
4 0
<span>A full outer shell has 8 valence electrons, and since each nitrogen has only five, they both need three more to get to a full outer shell. However, since they're the same atom, and they need the same amount of electrons, they're going to form a covalent bond, where they both SHARE three (if one gave three to the other, it would be down to two and even MORE unbalanced)</span>
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Be + O2 --&gt; BeO<br><br> Balance this and what's the type of reaction?
max2010maxim [7]

Answer:

2Be + O2 = 2BeO

its a synthesis

Explanation:

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2 years ago
What is filtration? ㅜㅜ ㅜㅜ
Aleks04 [339]

Answer:

filtration is the process of using a filter to remove solids from liquids or gasses.

Example:

an example of this is tea.

4 0
3 years ago
You mix 200. mL of 0.400M HCl with 200. mL of 0.400M NaOH in a coffee cup calorimeter. The temperature of the solution goes from
GuDViN [60]

Answer : The enthalpy of neutralization is, 56.012 kJ/mole

Explanation :

First we have to calculate the moles of HCl and NaOH.

\text{Moles of HCl}=\text{Concentration of HCl}\times \text{Volume of solution}=0.400mole/L\times 0.200L=0.08mol

\text{Moles of NaOH}=\text{Concentration of NaOH}\times \text{Volume of solution}=0.400mole/L\times 0.200L=0.08mol

The balanced chemical reaction will be,

HCl+NaOH\rightarrow NaCl+H_2O

From the balanced reaction we conclude that,

As, 1 mole of HCl neutralizes by 1 mole of NaOH

So, 0.08 mole of HCl neutralizes by 0.08 mole of NaOH

Thus, the number of neutralized moles = 0.08 mole

Now we have to calculate the mass of water.

As we know that the density of water is 1 g/ml. So, the mass of water will be:

The volume of water = 200mL+200L=400mL

\text{Mass of water}=\text{Density of water}\times \text{Volume of water}=1g/ml\times 400mL=400g

Now we have to calculate the heat absorbed during the reaction.

q=m\times c\times (T_{final}-T_{initial})

where,

q = heat absorbed = ?

c = specific heat of water = 4.18J/g^oC

m = mass of water = 400 g

T_{final} = final temperature of water = 27.78^oC=273+25.10=300.78K

T_{initial} = initial temperature of metal = 25.10^oC=273+27.78=298.1K

Now put all the given values in the above formula, we get:

q=400g\times 4.18J/g^oC\times (300.78-298.1)K

q=4480.96J

Thus, the heat released during the neutralization = -4480.96 J

Now we have to calculate the enthalpy of neutralization.

\Delta H=\frac{q}{n}

where,

\Delta H = enthalpy of neutralization = ?

q = heat released = -4480.96 J

n = number of moles used in neutralization = 0.08 mole

\Delta H=\frac{-4480.96J}{0.08mole}=-56012J/mole=-56.012kJ/mol

The negative sign indicate the heat released during the reaction.

Therefore, the enthalpy of neutralization is, 56.012 kJ/mole

8 0
3 years ago
5. Give one advantage of KIO3 as primary standard.​
alexdok [17]

Answer:

one advantage of KLO3 as a primary standard is that it is used to know concentration of a solution.

Explanation:

The reaction provides confirmation that the solution is at a specific concentration. Primary standards are often used to make standard solutions (a solution with a precisely known concentration

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3 years ago
Tell me a hypothesis for the corrosion experiment for iron nails?
Nastasia [14]
The more acidic the substance is, the more the iron nails will corrode (this obviously depends on what your experiment is but hope this helped in some way)
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3 years ago
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