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andrey2020 [161]
3 years ago
6

Iron metal reacts with elemental oxygen to form rust according to the unbalanced reaction, Fe(s) + O2(g) → Fe2O3(s),. What is th

e coefficient of the iron(III) oxide, Fe2O3(s), in the balanced reaction?
a
1
b
2
c
3
d
4
Time left for this assessment:
50:27
Chemistry
1 answer:
pochemuha3 years ago
3 0

Answer:

c. 3

Explanation:

The unbalanced reaction expression is given as:

          Fe  +  O₂  →   Fe₂O₃  

To balance the expression gives the coefficient of oxygen.

Assign the coefficients a,b, c and use a mathematical approach to solve this problem:

             aFe  +  bO₂  →  cFe₂O₃

Conserving Fe: a  = 2c

                    O:  2b  = 3c

Now let c = 1, a  = 2, b  = \frac{3}{2}

  Multiply through by 2,

             a = 4, b = 3 and c  = 2

 

               4Fe  +  3O₂  →   2Fe₂O₃  

The coefficient of O₂ is 3

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3 years ago
Molarity of a salt water solution of "0.47" moles of NaCl dissolved in a volume of 0.25L
asambeis [7]

Answer:

1.88 M

Explanation:

The following data were obtained from the question:

Mole of NaCl = 0.47 mole

Volume of solution = 0.25L

Molarity =?

Molarity is defined as the mole of solute per unit litre of the solution. It can represented mathematically as:

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Using the above formula, the molarity of the salt water solution can be obtained as follow:

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5 0
3 years ago
200g of solution of magnesium
diamong [38]

The mass of reacted magnesium chloride is 23.75g, percent by mass of solution magnesium chloride is 90.9%.

<h3>What is the relation between mass & moles?</h3>

Relation between the mass and moles of any substance will be represented as:

n = W/M, where

  • W = given mass
  • M = molar mass

Moles of MgCl₂ = 200g / 95g/mol = 2.1mol

Moles of NaOH = 20g / 0.5mol

Given chemical reaction is:

MgCl₂ + 2NaOH → 2NaCl + Mg(OH)₂

From the stoichiometry of the reaction it is clear that

  • 1 mole of MgCl₂ = reacts with 2 moles of NaOH
  • 0.5 mole of NaOH = reacts with (1/2)(0.5)=0.25 moles of MgCl₂

Mass of reacted MgCl₂ = (0.25mol)(95g/mol) = 23.75g

Percent by mass of MgCl₂ in the given solution mixture will be calculated as:

  • % by mass = (Mass of MgCl₂ / Total mass of mixture) × 100%
  • Percent by mass of MgCl₂ = (200/200+20)×100% = 90.0&

In the above reaction we obtain NaCl as a solid, and MgCl₂ is the limiting reagent in it, from which 2 moles of NaCl is produced means

  • 0.25 moles of MgCl₂ = produces 0.5 moles of NaCl

Mass of NaCl = (0.5mol)(58.5g/mol) = 29.25g

Hence, mass of reacted MgCl₂ is 23.75g, percent by mass of solution magnesium chloride is 90.9% and mass of the obtained solid is 29.25g.

To know more about mass & moles, visit the below link:

brainly.com/question/20838755

#SPJ1

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