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Marysya12 [62]
3 years ago
5

In understanding the trait of shyness, a behavioral geneticist will argue that:

Physics
1 answer:
MA_775_DIABLO [31]3 years ago
6 0

Answer:

4. genetics set a range for the level of shyness and environmental influences will interact with that range.

Explanation:

4. genetics set a range for the level of shyness and environmental influences will interact with that range.

Environmental changes determine to which range certain traits work. e.g the eggs hatch but only when certain heat is provided to them. similarly genetics work in all behaviuors but it shows when conditions are most favourable.

Every child is  born with an ability to learn but only those learn who are given the environment to do so.

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The answer would be A.
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The specific heat of a substance is the energy required to produce a certain change in _____________. A. appearance B. volume C.
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I think C I’m not 100% sure.
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What is the energy of a 4kg apple that is sitting on a 2 m high tree branch?
miv72 [106K]

78.4 joules is the energy of a 4 kg apple that is sitting on a 2 m high tree branch.

<u>Explanation: </u>

When an apple falls to the ground from a tree, its positional energy (stored as potential gravitational energy) turns into kinetic energy, during a fall. Chemical potential energy is chemical energy because it is food and potential energy as it can still have ability to move. So, in the given case, kinetic energy is zero.

To find potential energy, the formula would be

             \text { potential energy }(P . E)=m \times g \times h

Where, given

m – Mass – 4 kg

g-\text { Earth'sgravity }-9.8 \mathrm{m} / \mathrm{s}^{2} (Known value)

h – Height -  2 m

Substitute these values, we get

                  P . E=4 \times 9.8 \times 2=78.4 \text { joules }

8 0
3 years ago
A uniform solid sphere has a moment of inertia I about an axis tangent to its surface. What is the moment of inertia of this sph
arsen [322]

Answer:

option E

Explanation:

given,

I is moment of inertia about an axis tangent to its surface.

moment of inertia about the center of mass

I_{CM} = \dfrac{2}{5}mR^2.....(1)

now, moment of inertia about tangent

I= \dfrac{2}{5}mR^2 + mR^2

I= \dfrac{7}{5}mR^2...........(2)

dividing equation (1)/(2)

\dfrac{I_{CM}}{I}= \dfrac{\dfrac{2}{5}mR^2}{\dfrac{7}{5}mR^2}

\dfrac{I_{CM}}{I}=\dfrac{2}{7}

I_{CM}=\dfrac{2}{7}I

the correct answer is option E

4 0
3 years ago
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