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Troyanec [42]
3 years ago
6

The specific heat of a substance is the energy required to produce a certain change in _____________. A. appearance B. volume C.

temperature D. state
Physics
2 answers:
CaHeK987 [17]3 years ago
6 0
I think C I’m not 100% sure.
Tanya [424]3 years ago
5 0

Answer:

C. temperature

Explanation:

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A 4.20 gg coin is placed 15.0 cmcm from the center of a turntable. The coin has static and kinetic coefficients of friction with
ololo11 [35]

Answer:

Explanation:

mass of the coin m = 4.2 x 10⁻³ kg

radius of circular path r in which coin will move = 15 x 10⁻² m

coefficient of static friction μs = .7

at maximum angular velocity of ω , limiting force of friction will provide centripetal force to coin to rotate in circular path .

so centripetal force = frictional force

mω²r = μs x mg

ω²r = μs x g

ω² = μs x g / r

= .7 x 9.8 /  15 x 10⁻²

= 45.73

ω = 6.76 radian / s.

5 0
3 years ago
The first formant of your vocal system can be modeled as the resonance of an open-closed tube, the closed end being your vocal c
notka56 [123]

Answer:

290 Hz

Explanation:

7 0
2 years ago
Which property of a filled balloon would be unchanged on the moon where there's no air and less gravity?
grigory [225]
Its mass, I suppose. Unless the balloon explodes.
3 0
4 years ago
A sinusoidal wave of wavelength 2.00m and amplitude 0.100 m travels on a string with a speed of 1.00 m/s to the right. At t = 0
Shkiper50 [21]
  1. The frequency and angular frequency are 0.500 Hertz and 3.142 rad/s. respectively.
  2. The angular wave number is equal to 3.142 rad/m.
  3. The wave function for this wave is given by: y = Asin(kx - ωt + Φ).
  4. The equation of motion for the left end of the string is given by: y = 0.100sin(3.142x - 3.142t + 0).
  5. The equation of motion for the left end of the string at x = 1.50 m to the right is equal to y = 0.100sin(4.71 - 3.142t + 0).The maximum speed of any point on the string is 0.3142 m/s.

<h3>How to calculate the frequency and angular frequency?</h3>

First of all, we would determine the frequency of this wave by using this formula:

Frequency = wavelength/speed

Frequency = 0.100/2.00

Frequency = 0.500 Hertz.

For the angular frequency, we have:

Angular frequency, ω = 2πf

Angular frequency, ω = 2 × 3.142 × 0.500

Angular frequency, ω = 3.142 rad/s.

<h3>How to determine the angular wave number?</h3>

Angular wave number, k = 2π/∧

Angular wave number, k = (2 × 3.142)/2.00

Angular wave number, k = 3.142 rad/m.

<h3>How to determine the wave function for this wave?</h3>

Mathematically, the wave function for this wave is given by:

y = Asin(kx - ωt + Φ)

For the equation of motion for the left end of the string, we have:

y = 0.100sin(3.142x - 3.142t + 0)

For the equation of motion for the left end of the string at x = 1.50 m to the right, we have:

y = 0.100sin(3.142x - 3.142t + 0)

y = 0.100sin(3.142(1.5) - 3.142t + 0)

y = 0.100sin(4.71 - 3.142t + 0)

<h3>What is the maximum speed of any point on the string?</h3>

Vy = 0.100sin(- 3.142)cos(3.142x - 3.142t)

Vy ≤ 0.3142 m/s (since cosine varies +1 and -1).

Read more on wave function here: brainly.com/question/11181093

#SPJ4

Complete Question:

A sinusoidal wave of wavelength 2.00 m and amplitude 0.100 m travels on a string with a speed of 1.00 m/s to the right.  Initially, the left end of the string is at the origin.  Find:

(a) the frequency and angular frequency,

(b) the angular wave number, and

(c) the wave function for this wave.  

Determine the equation of motion in SI units for

(d) the left end of the string, and

(e) the point on the string at x = 1.50 m to the right of the left end.

(f) What is the maximum speed of any point on the string?

5 0
2 years ago
How would gravity cause planets to move if they did not have inertia?
daser333 [38]
I’d think the answer would be C. i’m just kinda guessing but my thought process is this (as simply as i can put it because physics is confusing):

so for example say you throw a ball across a flat surface. inertia is what keeps the ball rolling straight in a line, so unless you were to maybe put your hand in front of the ball or something, it would just go straight forever.

this is what happens with the planets. they go in a straight line, but since there’s gravity, the planets are also being pulled towards the sun. so gravity and inertia are why the planets orbit in the circle pattern they do. so when we remove inertia, we’re removing the state in which the planets keep going straight while being pulled towards a center point (the sun). this causes gravity to be the only factor in the planets orbiting. so that being said, the planets would just be pulled towards the sun. :)
4 0
3 years ago
Read 2 more answers
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