Answer:
The Acceleration will increase
Explanation:
Newton's Second Law of motion: It states that the rate of change of momentum is directly proportional to the applied force and takes places along the direction of the force.
It can be expressed mathematically as,
F ∝ m(v-u)/t
Where (v-u)/t = a
F = kma.
F = force, m = mass of the body, a = acceleration, k = constant of proportionality which tend to unity for a unit force, a unit mass, and a unit acceleration.
Therefore,
F = ma.
From the equation above,
If the net force acting on a body increase, while the mass of the body remains constant, the acceleration will also increase.
Answer:
Explanation:
The acceleration of a circular motion is given by
where 
is the angular velocity and 
is the radius.
Angular velocity is related to the period, T, by
Substitute into the previous formula.
This acceleration does not depend on the linear or angular displacement. Hence, the amount of rotation does not change it.
Answer:
The new period will be √6 *T
Explanation:
period ,T=2π√(L/g) ................equation 1
where T is the period on earth
gravitational acceleration on the moon is g/6
T1 = 2π√[L/(g/6)]
T1=2π√(6L/g) ...............equation 2
divide equation 2 by 1
T1/T =2π√(6L/g)÷2π√(L/g)
T1/T =√(6L/L)
T1/T =√6
T1 = √6 *T
The sun is the primary source of light. Other artificial sources are light bulb, torch light and some others. Thats all i can think of.
Answer:
5) 13 revolutions (approximately)
Explanation:
We apply the equations of circular motion uniformly accelerated :
ωf²= ω₀² + 2α*θ Formula (1)
Where:
θ : angle that the body has rotated in a given time interval (rad)
α : angular acceleration (rad/s²)
ω₀ : initial angular speed ( rad/s)
ωf : final angular speed ( rad/s)
Data:
ω₀ = 18 rad/s
ωf = 0
α = -2 rad/s² ; (-) indicates that the wheel is slowing
Revolutions calculation that turns the wheel until it stops
We apply the formula (1)
ωf²= ω₀² + 2α*θ
0 = (18)² + 2( -2)*θ
4*θ = (18)²
θ = (18)²/4 = 81 rad
1 revolution = 2π rad
θ = 81 rad * 1 revolution / 2πrad
θ = 13 revolutions approximately
