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Dmitrij [34]
3 years ago
13

Complete the table below by filling in the principal quantum number n and angular momentum quantum number l for each electron su

bshell listed.
subshell principal quantum number n angular momentum quantum number l
4f
7s
4p
7p
Chemistry
1 answer:
Alja [10]3 years ago
3 0

Answer:

For 4f  the principal quantum number, n is 4 and the angular momentum quantum number l is 3

7s: n = 7 and l = 0

4p: n = 4 and l = 1

7p: n = 7 and l = 1

Explanation:

The principal quantum number gives the energy level of the electron in an atom. It shows the shells in which an electron is in an atom.

if n = 1, 2, 3, 4...; it corresponds to K, L, M, N... shells in an atom

The numerical coefficient of the subshell gives the pricipal quantum number.

for instance in 4f, the principal quantum number, n is 4  because 4 is the coefficient.

The angular momentum quantum number, l gives the energy sublevel or subshell.

Angular momentum quantum number has integral values, l = 0, 1, 2, 3... which correspond to  s, p, d, f,..  orbitals.

Thus for 4f  the principal quantum number, n is 4 and the angular momentum quantum number l is 3

similarly, for 7s: n = 7 and l = 0

4p: n = 4 and l = 1

7p: n = 7 and l = 0

using similar approach for others

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<h3>How do molecules act at different temperatures?
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Cold molecules:

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Hot molecules:

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A simple example to understand this behavior of molecules is water because:

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Learn more about molecules in: brainly.com/question/19922822

6 0
3 years ago
How many moles of Ba(NO3)2 are there in 0.25 L of a 2.00 M Ba(NO3)2 solution?
klemol [59]

Answer:

0.5moles

Explanation:

Given parameters:

Volume of solution= 0.25L

Molarity of solution = 2.00M

Unknown:

Number of moles  = ?

Solution:

To solve this problem;

  Molarity is the number of moles of solute in a given volume of solution, so

 Number of moles  = molarity x volume

 Now insert the parameters and solve;

  Number of moles  = 0.25 x 2  = 0.5moles

6 0
3 years ago
Read 2 more answers
Iron(III) oxide can be reduced by carbon monoxide:Fe2O3 (s) + 3 CO (g) ⇌ 2 Fe (s) + 3 CO2 (g) Use the following thermodynamic da
Katena32 [7]

Answer:

k = 1,423x10⁵

Explanation:

For the reaction:

Fe₂O₃(s) + 3CO (g) ⇌ 2Fe(s) + 3CO₂(g)

You can obtain equilibrium constant, k, using:

ΔG° = -RT lnK <em>(1)</em>

<em></em>

ΔG° of the reaction is:

ΔGf° products - ΔGf° reactants, that means:

ΔG° = 2∆Gfº Fe(s) + 3∆Gfº CO₂(g) - (∆Gfº Fe₂O₃(s) + 3∆Gfº CO (g)

ΔG° = 2×0 + 3×-394,4kJ/mol - (-742,2kJ/mol + 3×-137,2kJ/mol)

<em>ΔG° = -29,4 kJ/mol</em>

<em />

Replacing in (1) knowing R = 8,314472x10⁻³ kJ/molK; T = 298K

-29,4 kJ/mol = -8,314472x10⁻³ kJ/molK 298K lnK

11,866 = lnK

<em>1,423x10⁵ = k </em>

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I hope it helps!

3 0
3 years ago
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sweet [91]

Answer:

monoxide

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trioxide

tetroxide

pentoxide

hexoxide

heptoxide

octoxide

nonoxide

Explanation:

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4 0
3 years ago
The pressure on 150 mL of a gas is increased from 500 mm Hg to 700 mm Hg at constant temperature. What is the new volume of the
Ivanshal [37]

Answer:

Option A. 107 mL

Explanation:

From the question given above, the following data were obtained:

Initial volume (V₁) = 150 mL

Initial pressure (P₁) = 500 mmHg

Final pressure (P₂) = 700 mmHg

Temperature = constant

Final volume (V₂) =?

The final volume of the gas can be obtained by using the Boyle's law equation as shown below:

P₁V₁ = P₂V₂

500 × 150 = 700 × V₂

75000 = 700 × V₂

Divide both side by 700

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4 0
3 years ago
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