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3 years ago

What is the concentration of H+ ions at a pH = 2?

1 answer:

s2008m [1.1K]3 years ago

3 0

Acidic and basic are two extremes that describe chemicals, just like hot and cold are two extremes that describe temperature. Mixing acids and bases can cancel out their extreme effects, much like mixing hot and cold water can even out the water temperature. A substance that is neither acidic nor basic is neutral.

The character of acidic, basic and neutral is defined by the concentration of hydrogen ions [H+](mol/L). A solution with a concentration of hydrogen ions higher than 10-7mol/L is acidic, and a solution with a lower concentration is alkaline (another way to say basic). Using the formula, pH=-log[H+], a pH of 7 is neutral, a pH less than 7 is acidic, and a pH greater than 7 is basic. As one can see from this formula, ten times a given concentration of hydrogen ions means one unit lower in terms of pH value (higher acidity), and vice versa.

The formula for ph is given by:
pH=−log10[H+]
What is the concentration of H+ ions at a pH = 2?
In calculating for the concentration of hydrogen ion, the formula is given by:
[H+]=(10)^(-pH)

Solution:

[H+]=(10)^(-2)
[H+]=0.01 M

What is the concentration of OH– ions at a pH = 2?
pH+pOH=14
2+pOH=14
pOH=12

[OH-]=(10)^(-pOH)
[OH-]=(10)^(-12)
[OH-]=1.0x10^-12 M

What is the ratio of H+ ions to OH– ions at a pH = 2?
The ratio is 0.01:1.0x10^-12 which is equal to 0.000000000001

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Please choose the correct number (associated with the vocab word) from the drop down menu that matches the definition

baherus [9]

Q1. -------- a specific way that a quantity may increase over time

1. Exponential growth

2. Biotic

3. Trait

4. Succession

Answer:

1. Exponential growth

Explanation:

Exponential growth is a specific way that a quantity may increase over time. The instantaneous rate of change of a quantity with respect to time is proportional to the quantity itself. When growth becomes more rapid in relation to the growing total number, then it becomes exponential.

Example: Latest updates of COVID-19. For today, the number of infected people cases from COVID-19 is 190,000. By observing the graph, to reach 100,000 the number of infected patient cases, it took 3 months and the other 90,000 patients were infected in just 15 days.

Q2. ------- is the inherent inclination of a living organism towards a particular complex behavior.

1. Abiotic

2. Biotic

3. Innate behavior

Answer:

3. Innate behavior

Explanation:

Innate behavior is behavior that occurs naturally in all members of a species. These behaviors do not have to be learned or practiced.

Example: When a human baby born, he already knows how to suck mother breast to get milk. He never learned before. As he grew up, he knows how to grasp things.

8 0

3 years ago

The metabolic oxidation of glucose, C6H12O6, in our bodies produces CO2, which is expelled from our lungs as a gas.

enot [183]

Answer:

$\large \boxed{\text{21.6 L}}$

Explanation:

We must do the conversions

mass of C₆H₁₂O₆ ⟶ moles of C₆H₁₂O₆ ⟶ moles of CO₂ ⟶ volume of CO₂

We will need a chemical equation with masses and molar masses, so, let's gather all the information in one place.

Mᵣ: 180.16

C₆H₁₂O₆ + 6O₂ ⟶ 6CO₂ + 6H₂O

m/g: 24.5

(a) Moles of C₆H₁₂O₆

$\text{Moles of C$_{6}$H$_{12}$O}_{6} = \text{24.5 g C$_{6}$H$_{12}$O}_{6}\times \dfrac{\text{1 mol C$_{6}$H$_{12}$O}_{6}}{\text{180.16 g C$_{6}$H$_{12}$O}_{6}}\\\\= \text{0.1360 mol C$_{6}$H$_{12}$O}_{6}$

(b) Moles of CO₂

$\text{Moles of CO}_{2} =\text{0.1360 mol C$_{6}$H$_{12}$O}_{6} \times \dfrac{\text{6 mol CO}_{2}}{\text{1 mol C$_{6}$H$_{12}$O}_{6}} = \text{0.8159 mol CO}_{2}$

(c) Volume of CO₂

We can use the Ideal Gas Law.

pV = nRT

Data:

p = 0.960 atm

n = 0.8159 mol

T = 37 °C

(i) Convert the temperature to kelvins

T = (37 + 273.15) K= 310.15 K

(ii) Calculate the volume

$\begin{array}{rcl}pV &=& nRT\\\text{0.960 atm} \times V & = & \text{0.8159 mol} \times \text{0.082 06 L}\cdot\text{atm}\cdot\text{K}^{-1}\text{mol}^{-1} \times \text{310.15 K}\\0.960V & = & \text{20.77 L}\\V & = & \textbf{21.6 L} \\\end{array}\\\text{The volume of carbon dioxide is $\large \boxed{\textbf{21.6 L}}$}$

7 0

2 years ago

HELP DUE MONDAY!! Don’t understand

Katyanochek1 [597]

Answer:

Concept: Chemical Analysis

You need to start by graphing the data and then analyzing it.
We can see that the horse has a distance in meters of 980 at the end of the 10 seconds hence it is the fastest.
The horse line has a linearly representation, while the alternate line has parabolic tendencies towards the end. The steeper line indicates a faster change in time or velocity which results in a greater distance traveled indicating that the horse is faster.
*I have confidence you can graph that*

5 0

2 years ago

What is the molarity of the solution produced when 8.0g NaOH is dissolved in sufficient water to prepare 500.mL of solution?

Sindrei [870]

Answer:

Molarity = 0.4M

Explanation:

Molar mass of NaOH (M)= 40

m= 8g, V= 500ml=0.5L

n= m/M=[8/40]= 0.2mol

Applying

n= CV

0.2= C×0.5

C= 0.4M

8 0

2 years ago

A sample of 19 mg of 9-fluorenone is dissolved in 5 mL of diethyl ether. The resulting organic

maks197457 [2]

Answer:

15.70mg would remain

Explanation:

Partition coefficient is used to extract or purify a solute from a solvent selectively to avoid interference from other substances. For the problem, formula is:

Kp = Concentration 9-fluorenone in ether / Concentration of solute in H₂O

After the solute, 9-fluorenone, is extracted with water, the mass that remains in ether is:

(19mg - X)

Where X is the mass that now is in the aqueous phase

Replacing in Kp formula:

9.5 = (19mg - X) / 5mL / (X /10mL)

0.95X = 19mg - X / 5mL

4.75X = 19 - X

5.75X = 19

X = 19 / 5.75

X = 3.30mg

That means 9-fluorenone that remain in the ether layer is:

19mg - 3.30mg =

<h3>15.70mg would remain</h3>

8 0

3 years ago