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liubo4ka [24]
2 years ago
8

Pls help I will give brainlist

Chemistry
1 answer:
Mandarinka [93]2 years ago
3 0

Answer:putis

Explanation:

ai domti now

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kvv77 [185]

Answer:

It's me mario

Explanation:

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2 years ago
Hurry answer this pls so i can pass
makvit [3.9K]
A I took the test already and it’s A for sure because the syrup has less water in it. It sucks the water out of the egg.
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3 years ago
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Explain how melting points are used to identify compounds and determine purity. g\
Oduvanchick [21]

Answer: melting points are major means of identifying pure compounds.

Explanation:

A pure compound can be identified by its melting point because, a pure compound will have a sharp melting point while an impure compound will melt over a temperature range. If presented with a pure sample of an unknown solid, its melting point can tell us what the identity of the compound. Similarly, melting point analysis can show the purity of a known solid. If the known solid has a sharp melting point, then it is pure.

4 0
3 years ago
The pH of a nearby stream is tested and found to be basic. Which pH could be a valid result from the testing of the stream? A. 5
Shkiper50 [21]
On the pH scale, simply put, 1 is the most acidic, 14 the most basic, and 7 is neutral. So if it is basic, it would have to be above 7, and 8 is the only one above seven, so your answer is D.
4 0
3 years ago
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The solubility of magnesium fluoride, , in water is g/L. What is the solubility (in grams per liter) of magnesium fluoride in 0.
Gnoma [55]

Answer:

1.457*10^-8 grams

Explanation:

First we want to find the molar concentration of MgF2. We can do this by dividing 0.016 (the solubility in grams of MgCl2 in a litre of water) by its molar mass (approx. 62.3 grams). Thus, the molar solubility of MgF2 is 2.57*10^-4 M.

Next, we must calculate the Ksp of MgF2. The equilibrium expression is:

MgF2⇄Mg+2F

Thus   Ksp=[Mg^+][F^-]^2

This means that, in equilibrium, there are 2.57*10^-4 M of M^+ and 5.136*10^-4 M of F^-

Plugging in the above information, our Ksp for MgF2 is approximately 6.78*10^-11

Next we will need to use the RICE table. Since there is already 0.29M of NaF dissolved, there is initially 0.29M of F^-.

R: MgF2 ⇄ Mg^{+}+2F^-

I:    N/A        0     0.29M

C:   N/A         +x      +x

--------------------------------------------

E:   N/A         x     0.29+x  

To make calculations easier, we will assume that 0.29+x≈0.29

This means that Ksp=0.29x=6.78*10^-11

Therefore, x≈2.338*10^-10M

Multiply that by 62.3 and we get around 1.457*10^-8 grams.

3 0
2 years ago
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