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Answer:
A 60 kg person standing on a platform at the surface of Saturn and they jumped, they would have to push with a force greater than 540 N
Explanation:
The gravitational attraction between an object on the surface of a planet and the planet is given by the weight of the object
Therefore the force needed to be applied for an object to lift off the surface of a planet = The weight of the object
The weight of the object on the surface of a planet = m × g
Where;
m = The mass of the object
g = The strength of gravity on the planet's surface in N/kg
The given parameters are;
The mass of the person standing on a platform at the surface of Saturn, m = 60 kg
The strength of gravity on the surface of Saturn = 9 N/kg
Therefore, we have;
The weight of the person = The force greater than which the person would have to push on the surface of Saturn so as to Jump = The weight of the person on the surface of Saturn = 60 kg × 9 N/kg = 540 N
Therefore, for a 60 kg person standing on a platform at the surface of Saturn and they jumped, they would have to push with a force greater than 540 N.
Answer:
the number of neutrons and protons in an atom
Answer:
165.77J
Explanation:
M₁ = 0.107kg
u₁ = 300m/s
m₂ = 3kg
u₂ = 0
v =
m₁u₁ + m₂u₂ = (m₁ + m₂)V
(0.107*300) + 0 = (0.107 + 3)V
V = 32.1 / 3.107 = 10.33m/s
kinetic energy of the system after collision =
½m1v² + ½m2v²
K.E = ½(m1 + m2)v²
K.E = ½(0.107+3) * 10.33²
K.E = 165.77J
Answer:
(a) v = 65.35 m/s
(b) ac = 82.16 m/s²
Explanation:
Kinematic of the blades of the wind turbine
The blades of the wind turbine describe circular motion and the formulas that apply to this movement are as follows:
v = ω * R Formula (1)
Where:
v : tangential velocity (m/s)
ω : angular velocity (rad/s)
R : radius of the particle path (m)
The velocity vector is tangent at each point to the trajectory and its direction is that of movement. This implies that the movement has centripetal acceleration (ac):
ac = ω²* R Formula (1)
ac : centripetal acceleration (m/s²)
Data:
ω= 12 rpm = 12 rev/min
1 rev = 2π rad
1 min = 60 s
ω= 12 rev/min = 12 (2π rad)/(60 s)
ω = 1.257 rad/s
R = 52 m
(a)Tangential velocity at the tip of a blade (v)
We apply the formula (1)
v = ω* R
v = ( 1.257)* (52) = 65.35 m/s
(a) Centripetal acceleration at the tip of a blade (ac)
We apply the formula (2)
ac = ω²*R
ac = ( 1.257)²* (52) = 82.16 m/s²
