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3 years ago

5

A bowling pin is thrown vertically upward such that it rotates as it moves through the air, as shown in the figure. Initially, t

he center of mass of the bowling pin is moving upward with a speed vi of
10 The maximum height of the center of mass of the bowling pin is most nearly

1 answer:

zheka24 [161]3 years ago

3 0

Answer:

Explanation:

In projectile, the formula for calculating the maximum height reached by the pin is expressed as;

H = u²/2g

u is the speed/velocity = 10m/s

g is the acceleration due to gravity = 9.81m/s²

Substitute

H = 10²/2(9.81)

H = 100/19.62

H = 5.097m

Hence the maximum height of the center of mass of the bowling pin is most nearly 5.0m

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The maximum acceleration $a_{max}$ is when the force is maximum $F_{max}$ , as well :

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