You can go to a website about that it will give you the answers
Answer:
Mn(s)/Mn^2+(aq)//Co^2+(aq)/Co(s)
Explanation:
In writing the cell notation for an electrochemical cell, the anode is written on the left hand side while the cathode is written on the right hand side. The two half cells are separated by two thick lines which represents the salt bridge.
For the cell discussed in the question; the Mn(s)/Mn^2+(aq) is the anode while the Co^2+(aq)/Co(s) half cell is the cathode.
Hence I can write; Mn(s)/Mn^2+(aq)//Co^2+(aq)/Co(s)
The concentration of [CI-] : 0.617 M
<h3>Further explanation</h3>
FeCl₃ dissolved in 450 mL of solution(will dissociate )
Reaction
FeCl₃⇒Fe³⁺+3Cl⁻
- mol FeCl₃(MW=162,2 g/mol)
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