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3 years ago

Which state of matter are required for energy transfer to occur when radiant energy is the source?

Chemistry

1 answer:

lisabon 2012 [21]3 years ago

8 0

Answer:

No state of matter is required

Explanation:

When <em>radiant energy </em>is the source, we are talking about <em>energy transfer by radiation, </em>so matter is not needed for the energy to be transfered.

An example of this could be the Sun, it heats up the Earth by radiation, even through the vacuum of outer space, where there is next to no matter.

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Boyle's law only works when a gas is kept at a constant temperature. Experimentally this is very tricky as changes in pressure o

Lady bird [3.3K]

The heat that creates this temperature change coming from change in the internal energy of the system as per as first law of thermodynamics.

<h3>What is Boyle's law ?</h3>

A law stating that the pressure of a given mass of an ideal gas is inversely proportional to its volume at a constant temperature.

As we know, Boyle's law only works when the gas is kept at a constant temperature

Here,

When volume of gases decreased, it means work done has occurred on the system, so the work done is used for raising internal energy of the gas and the other is released as the thermal energy.

So,

According to 1st law of thermodynamics,

we know Q = ΔU + W i.e, change in internal energy and work done. So this is a reason. Changing temperature occurs.

Learn more about Internal enrgy here ;

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2 years ago

The lighted half of the moon faces away from Earth during the _____ moon phase.

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The lighted half of the moon faces away from the earth during the New Moon phase

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4 years ago

Which expression is equal to the number of grams (g) in 2.43 kilograms (kg)?

Gre4nikov [31]

2.43 kilograms is equal to 2430 grams because 1 kilogram is equal to 1000 grams.

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3 years ago

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What kind of bond is the result of the transfer of an electron?

MrRa [10]

An Ionic bond is the result of transfer of electrons between atoms

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3 years ago

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Write the balanced equation for the reaction of aqueous Pb ( ClO 3 ) 2 Pb(ClO3)2 with aqueous NaI . NaI. Include phases. chemica

FinnZ [79.3K]

<u>Answer:</u> The mass of precipitate (lead (II) iodide) that will form is 119.89 grams

<u>Explanation:</u>

To calculate the number of moles for given molarity, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}$

Molarity of NaI solution = 0.130 M

Volume of solution = 0.400 L

Putting values in above equation, we get:

$0.130M=\frac{\text{Moles of NaI}}{0.400L}\\\\\text{Moles of NaI}=(0.130mol/L\times 0.400L)=0.52mol$

The balanced chemical equation for the reaction of lead chlorate and sodium iodide follows:

$Pb(ClO_3)_2(aq.)+2NaI(aq.)\rightarrow PbI_2(s)+2NaClO_3(aq.)$

The precipitate (insoluble salt) formed is lead (II) iodide

By Stoichiometry of the reaction:

2 moles of NaI produces 1 mole of lead (II) iodide

So, 0.52 moles of NaI will produce = $\frac{1}{2}\times 0.52=0.26mol$ of lead (II) iodide

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Moles of lead (II) iodide = 0.26 moles

Molar mass of lead (II) iodide = 461.1 g/mol

Putting values in above equation, we get:

$0.26mol=\frac{\text{Mass of lead (II) iodide}}{461.1g/mol}\\\\\text{Mass of lead (II) iodide}=(0.26mol\times 461.1g/mol)=119.89g$

Hence, the mass of precipitate (lead (II) iodide) that will form is 119.89 grams

4 0

3 years ago