Answer:
27.3 kJ/mol
Explanation:
Step 1: Given data
- Temperature 1 (T₁): 298 K
- Vapor pressure 1 (P₁): P₁
- Temperature 2 (T₂): 318 K
- Vapor pressure 2 (P₂): 2 P₁
Step 2: Calculate the enthalpy of vaporization of this liquid
We will use the Clausius–Clapeyron equation.
ln (P₂/P₁) = -ΔHvap/R × (1/T₂ - 1/T₁)
ln 2 = -ΔHvap/(8.314 J/K.mol) × (1/318 K - 1/298 K)
ΔHvap = 2.73 × 10⁴ J/mol = 27.3 kJ/mol
Answer:
A. to absorb carbon dioxide from the atmosphere and use it to make sugar
Explanation:
Green plants with the help of their green coloring pigment called chlorophyll helps to absorb sunlight. This sunlight helps in the process Called photosynthesis in which plants manufacture food (sugar) using CO2(Carbon dioxide)and Water to give Oxygen and Sugar. The oxygen is released back into the atmosphere.
The answer is the boiling point because when you want to change the liquid into a gas you should boil it :)))
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The minimum mass of NaHCO3 that must be added to the spill to neutralize the acid is 27.216 grams
<h3>calculation </h3>
write the balanced chemical equation
2NaHCO3 +H2SO4 → Na2SO4 +2H2O +2CO2
find the moles of H2SO4 = molarity x volume in liters
volume in liters = 27/1000=0.027 l
moles is therefore= 0.027 x6=0.162 moles
by use of mole ratio of NaHCO3: H2SO4 which is 2:1 the moles of NaHCO3=0.162 x2=0.324 moles
mass of NaHCO3= moles of NaHCO3 x molar mass of NaHCO3(84g/mol)
= 84g/mol x 0.324=27.216 grams
Answer:
The two conditions that can limit the usefulness of the kinetic-molecular theory in describing gas behavior are "high pressure" and "low temperatures". At low temperatures or high pressures, real gases deviate significantly from ideal gas behavior.
Explanation: