Electronic configuration of the atom describes the arrangemnet of electrons in different shells and subshells ( sublevels).
Now , there are 4 types of sublevels: s, p , d and f . These sublevels have orbital which are spaces with high probability of having an electron and each orbital can have maximum 2 electrons.
Therefore,
s-sublevel has 1 orbital - it can have maximum 2 electrons.
p-sublevel has 3 orbitals - it can have maximum 6 electrons
d-sublevel has 5 orbitals - it can have maximum 10 electrons
f-sublevel has 7 orbitals - it can have maximum 14 electrons.
Hence, the acsending order of sublevels in terms of maximum number of electrons is:
<h2>s < p < d < f</h2>
I think answer should be the last option I hope this helps let me know if it’s correct thanks
I think it’s water evaporation I’m not sure tho
Answer:
(D) chlorine has a greater ionization energy than sodium
Explanation:
Sodium is the element of the group 1 and period 3 which means that the valence electronic configuration is ![[Ne]3s^1](https://tex.z-dn.net/?f=%5BNe%5D3s%5E1)
.
Chlorine is the element of the group 17 and period 3 which means that the valence electronic configuration is ![[Ne]3s^23p^5](https://tex.z-dn.net/?f=%5BNe%5D3s%5E23p%5E5)
.
Ionization energy is the minimum amount of energy which is required to knock out the loosely bound valence electron from the isolated gaseous atom.
<u>Thus, removal of one electron in sodium is easy as it will gain noble gas configuration and become stable. But this case does not exist in chlorine and hence, chlorine has a greater ionization energy than sodium.</u>
So,
Sodium is much more apt to exist as a cation than chlorine because chlorine has a greater ionization energy than sodium.
Answer:
Solubility in water Anhydrous: 74.5 g/100 mL (20 °C) Hexahydrate: 49.4 g/100 mL (−25 °C) 59.5 g/100 mL (0 °C) 65 g/100 mL (10 °C) 81.1 g/100 mL (25 °C) 102.2 g/100 mL (30.2 °C) α-Tetrahydrate: 90.8 g/100 mL (20 °C) 114.4 g/100 mL (40 °C) Dihydrate: 134.5 g/100 mL (60 °C) 152.4 g/100 mL (100 °C)
