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Andre45 [30]
3 years ago
12

What is the midpoint of the segment (0,9) and (5,4)

Mathematics
1 answer:
Debora [2.8K]3 years ago
3 0
This is easy the answer is 56
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Which describes the correlation shown in the scatterplot?
xenn [34]

Answer:

I don't know..

Sorry for spamming...

6 0
3 years ago
ASAP!! Please help me. I will not accept nonsense answers, but will mark as BRAINLIEST if you answer is correctly with solutions
Alex73 [517]

The correct answer should be D.

4 0
3 years ago
Which pattern has the fastest growth rate?
kotykmax [81]

▪▪▪▪▪▪▪▪▪▪▪▪▪  {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪

The pattern having the fastest growth rate is :

  • D
3 0
2 years ago
Find the total surface area of the triangular prism
GuDViN [60]

Answer:

1,008\:\mathrm{cm^2}

Step-by-step explanation:

The total surface area of this triangular prism consists of three rectangles and two triangles. Adding the areas of each of these shapes allows us to find the total surface area of this 3D figure:

Area of both triangles:

2\cdot \frac{1}{2}\cdot12\cdot 14=168\:\mathrm{cm^2}

Area of all three rectangles:

15\cdot 20 +13\cdot 20+14\cdot 20=840\:\mathrm{cm^2}

Therefore, the total surface area of this figure is:

840+160=\fbox{$1,008\:\mathrm{cm^2}$} \: \checkmark

3 0
3 years ago
In a recently administered iq test, the scores were distributed normally, with mean 100 and standard deviation 15. what proporti
iragen [17]

To solve for proportion we make use of the z statistic. The procedure is to solve for the value of the z score and then locate for the proportion using the standard distribution tables. The formula for z score is:

z = (X – μ) / σ

where X is the sample value, μ is the mean value and σ is the standard deviation

 

when X = 70

z1 = (70 – 100) / 15 = -2

Using the standard distribution tables, proportion is P1 = 0.0228

 

when X = 130

z2 = (130 – 100) /15 = 2

Using the standard distribution tables, proportion is P2 = 0.9772

 

Therefore the proportion between X of 70 and 130 is:

P (70<X<130) = P2 – P1

P (70<X<130) = 0.9772 - 0.0228

P (70<X<130) = 0.9544

 

Therefore 0.9544 or 95.44% of the test takers scored between 70 and 130.

6 0
3 years ago
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