Explanation:
<em>For</em><em>ce</em><em> </em><em>per</em><em> </em><em>uni</em><em>t</em><em> </em><em>area</em><em> </em><em>is</em><em> </em><em>call</em><em>ed</em><em> </em><em>Pres</em><em>sure</em><em>.</em>
It might be c I'm not sure either. Hope I helped
Answer:
a) i = -9.63 cm
, h ’= .0.24075 cm erect
b) i = 259.74 cm
,
Explanation:
For this exercise let's start by finding the focal length of the lens
1 / f = (n-1) (1 / R₁ - 1 / R₂)
1 / f = (1.70 -1)) 1 / ∞ - 1/13)
1 / f = 0.0538
f = - 18.57 cm
Now we can use the constructor equation
1 / f = 1 / o + 1 / i
1 / i = 1 / f - 1 / o
1 / i = -1 / 18.57 -1/20
1 / i = -0.1038 cm
I = -9.63 cm
For the height of the
image let's use magnification
m = h '/ h = - i / o
h ’= -h i / o
h ’= - 0.5 (-9.63) / 20
h ’= .0.24075 cm
b) we invert the lens
The focal length is
1 / f = (1.70 -1) (1/13 - 1 / int)
1 / f = 0.0538
f = 18.57 cm
1 / i = 1 / f -1 / o
1 / I = 1 / 18.57 - 1/20
1 / I = 3.85 10-3
i = 259.74 cm
h ’= - 0.5 259.74 / 20
h ’= 6.4935 cm
C- Stratus clouds are the rainy clouds.
Hope this helps!
When a satellite is revolving into the orbit around a planet then we can say
net centripetal force on the satellite is due to gravitational attraction force of the planet, so we will have
now we can say that kinetic energy of satellite is given as
also we know that since satellite is in gravitational field of the planet so here it must have some gravitational potential energy in it
so we will have
so we can say that energy from the fuel is converted into kinetic energy and gravitational potential energy of the satellite
