At the same instant that a 0.50-kg ball is dropped from 25m above Earth,? At the same instant that a 0.50-kg ball is dropped fro
m 25m aboveEarth, a second ball, with a mass of 0.25 kg, is thrown straight upward from Earth’ssurface with an initial speed of 15m/s. They move along nearby lines and pass each other without colliding.At the end of 2.0 s the velocity of the center of mass of the two-ball system is:
1 answer:
You might be interested in
Answer:
The drag coefficient is
Explanation:
From the question we are told that
The density of air is
The diameter of bottom part is
The power trend-line equation is mathematically represented as
let assume that the velocity is 20 m/s
Then
The drag coefficient is mathematically represented as
Where
is the drag force
is the density of the fluid
is the flow velocity
A is the area which mathematically evaluated as
substituting values
Then
Answer:
a) 0 metres
b) From time 0 s to 10 s , the car was accelerated. Its velocity accelerated from 0m/s to 20 m/s
c) 20 m/s
Explanation:
a) <em>Formula of displacement= velocity x time</em>
time=40 s
velocity =0 m/s
∴ displacement= 0 x 40 = 0 m
Magnitude of displacement is 0 m
b) The increase in velocity shows that there has been acceleration.
c) The average velocity of the car is = {initial velocity + final velocity}
=
=20
Therefore, the magnitude of the average velocity of the car is 20 m/s