Answer:
They both involve writing a rate.
Step-by-step explanation:
EDGENUITY ANSWER
Answer:
89.25
Step-by-step explanation:
2pound of walnut= 25.50
1 pound of walnut= 12.75
7punds of walnut= 89.25
7pounds of walnut= 12.75* 7=89.25
![y' = \frac{dy}{dx}](https://tex.z-dn.net/?f=y%27%20%3D%20%5Cfrac%7Bdy%7D%7Bdx%7D%20)
seperable differential equations will have the form
![\frac{dy}{dx} = F(x) G(y)](https://tex.z-dn.net/?f=%5Cfrac%7Bdy%7D%7Bdx%7D%20%3D%20F%28x%29%20G%28y%29)
what you do from here is isolate all the y terms on one side and all the X terms on the other
![\frac{dy}{G(y)} = F(x) dx](https://tex.z-dn.net/?f=%5Cfrac%7Bdy%7D%7BG%28y%29%7D%20%3D%20F%28x%29%20dx)
just divided G(y) to both sides and multiply dx to both sides
then integrate both sides
![\int \frac{1}{G(y)} dy = \int F(x) dx ](https://tex.z-dn.net/?f=%5Cint%20%5Cfrac%7B1%7D%7BG%28y%29%7D%20dy%20%3D%20%5Cint%20F%28x%29%20dx%0A%0A)
once you integrate, you will have a constant. use the initial value condition to solve for the constant, then try to isolate x or y if the question asks for it
In your problem,
![G(y) = \sqrt{1-y^2} F(x) = 2x](https://tex.z-dn.net/?f=G%28y%29%20%3D%20%5Csqrt%7B1-y%5E2%7D%0A%0AF%28x%29%20%3D%202x)
so all you need to integrate is
Answer:
I think you are missing something from the question, but if you were to find out how much you would get paid for a certain amount of hours from $12 per hour, then the formula would be:
Step-by-step explanation:
Let h = no. of hours worked
$12 * h
<u>Given</u>:
Given that O is the center of the circle.
The radius of the circle is 3 m.
The measure of ∠AOB is 30°
We need to determine the length of the major arc ACB
<u>Measure of major ∠AOB:</u>
The measure of major angle AOB can be determined by subtracting 360° and 30°
Thus, we have;
![Major \ \angle AOB=360-30](https://tex.z-dn.net/?f=Major%20%5C%20%5Cangle%20AOB%3D360-30)
![Major \ \angle AOB=330^{\circ}](https://tex.z-dn.net/?f=Major%20%5C%20%5Cangle%20AOB%3D330%5E%7B%5Ccirc%7D)
Thus, the measure of major angle is 330°
<u>Length of the major arc ACB:</u>
The length of the major arc ACB can be determined using the formula,
<u></u>
<u></u>
Substituting r = 3 and
, we get;
![m \widehat{ACB}=(\frac{330}{360})2 \pi (3)](https://tex.z-dn.net/?f=m%20%5Cwidehat%7BACB%7D%3D%28%5Cfrac%7B330%7D%7B360%7D%292%20%5Cpi%20%283%29)
![m \widehat{ACB}=\frac{1980}{360}\pi](https://tex.z-dn.net/?f=m%20%5Cwidehat%7BACB%7D%3D%5Cfrac%7B1980%7D%7B360%7D%5Cpi)
![m \widehat{ACB}=5.5 \pi](https://tex.z-dn.net/?f=m%20%5Cwidehat%7BACB%7D%3D5.5%20%5Cpi)
Thus, the length of the major arc ACB is 5.5π m