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pshichka [43]
3 years ago
11

If the force of gravity increases, which measurement will change and how?

Physics
2 answers:
77julia77 [94]3 years ago
8 0

If the force of gravity increases, then <em>weight increases.</em>

Simple easy explanation: The force of gravity IS what we call "weight".

Better explanation: The force of gravity between two masses tries to pull the masses together.  If gravity increases, then the force pulling the masses together increases.

alekssr [168]3 years ago
5 0
In physics we refer to how heavy the object is as the mass.

Fg = mass x acceleration due to gravity

Force is directly proportional to mass, thus if force of gravity increases mass also increases.
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Determine the inductance L of a 0.65-m-long air-filled solenoid 3.2 cm in diameter containing 8400 loops.
den301095 [7]

Answer:

The inductance is  L  = 0.1097 \ H

Explanation:

From the question we are told that

  The  length is  l  =  0.65 \ m

   The  diameter is  d =  3.2 cm  = 0.032 \ m

    The  number of loops is  N  =  8400

Generally the radius is evaluated as

       r = \frac{ 0.032 }{2}  =  0.016 \ m

The  inductance is mathematically represented as

      L  =  \frac{ \mu_o  *  N^2  * A }{ l }

Here \mu_o is the permeability of free space with value  \mu_o   = 4\pi * 10^{-7} N/A^2

A is the cross-sectional area which is mathematically evaluated as

             A =  \pi  r^2

=>        A =  3.142 *  (0.016)^2

=>        A =  0.000804 \ m^2

 =>  L  =  \frac{   4\pi * 10^{-7} *  8400^2  * 0.000804  }{ 0.65 }

=>    L  = 0.1097 \ H

5 0
3 years ago
When the displacement in SHM is one-half the amplitude xm, what fraction of total energy is (a) kinetic energy and (b) potential
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Answer:

b

Explanation:

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3 years ago
A ship's propeller of diameter 3 m makes 10.6 revolutions in 30s. What is the angular velocity of the propeller?
ycow [4]

Answer:

The angular velocity of the propeller is 2.22 rad/s.

Explanation:

The angular velocity (ω) of the propeller is:  

\omega = \frac{\Delta \theta}{\Delta t}                              

Where:

θ: is the angular displacement = 10.6 revolutions

t: is the time = 30 s

\omega = \frac{\Delta \theta}{\Delta t} = \frac{10.6 rev*\frac{2\pi rad}{1 rev}}{30 s} = 2.22 rad/s

Therefore, the angular velocity of the propeller is 2.22 rad/s.

I hope it helps you!

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