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4 years ago

When light waves pass through the lenses of a pair of glasses, the light waves ______________ .

Physics

1 answer:

e-lub [12.9K]4 years ago

4 0

refracts. Hope this helped.

When light enters a pair of glasses, it ______________ when it hits the glass.

When light waves pass through the lenses of a pair of glasses, the light waves ______________ .

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(2) Put 5kg mass at left side (at 2m). This is fixed throughout the experiment! (3) Try to balance by putting 5kg mass at the ri

dmitriy555 [2]

We can conclude that as the mass on the right increases, the distance of the mass towards the right decreases. Also when the two masses balance, the net torque is zero.

<h3>What is torque</h3>

The torque experienced by an object a given position is the product of the applied force and the perpendicular distance of the object.

When 5 kg mass is at 2 m on the left, another 5 kg at 2 m on the right will balance it.

$\tau _{net} = (2 \times 5 \times 9.8) - (2 \times 5 \times 9.8)\\\\\tau _{net} = 0$

<h3>Position of 10 kg mass on the right</h3>

Apply principle of moment

$F_1r_1 = F_2r_2\\\\(m_1gr_1) = (m_2gr_2)\\\\r_2 = \frac{m_1gr_1}{m_2g} \\\\r_2 = \frac{m_1 r_1}{m_2} \\\\r _2 = \frac{5 \times 2}{10} \\\\r_2 = 1 \ m$

<h3>Net torque</h3>

$\tau_{et} = m_2gr_2 - m_1gr_1\\\\\tau_{et} = (10 \times 9.8 \times 1) - (5 \times 9.8 \times 2)\\\\\tau_{et} = 0$

<h3>Position of the 20 kg mass</h3>

$r_2 = \frac{5 \times 2}{20} \\\\r_2 = 0.5 \ m$

<h3>Net torque</h3>

$\tau_{et} = m_2gr_2 - m_1gr_1\\\\\tau_{et} = (20 \times 9.8 \times 0.5) - (5 \times 9.8 \times 2)\\\\\tau_{et} = 0$

Thus, we can conclude that as the mass on the right increases, the distance of the mass towards the right decreases. Also when the two masses balance, the net torque is zero.

Learn more about principles of moment here: brainly.com/question/26117248

7 0

2 years ago

What acceleration did you measure from the video? Does this match the acceleration you calculated in the first step?

OLEGan [10]

Explanation:

dont know so sorryyyyyyyyy

6 0

3 years ago

How do you find the value of e?

Nadusha1986 [10]

<h3>Answer: 22.48°</h3><h3 /><h3>Explanation:</h3>

refractive index = sin i / sin e

where i is the angle of incidence

e is the angle of refraction

1.5 = sin 35 / sin e

1.5 = 0.5736/sin e

sin e = 0.5736/ 1.5

sin e = 0.3824

e = 22.48°

<h3 />

3 0

3 years ago

a) When we were examining the Electromagnetic Tab, we saw that a flow of electrons or a current as we say it, creates a magnetic

olga nikolaevna [1]

Answer:

Magnetic field can be used to produce current, infact a changing magnetic field can produce current.

A changing magnetic field in a loop causes the flux linked with the loop to change in turn generating a emf in the loop and therefore a current.

For a loop of area A and resistance R.

I =dPhi/dt/R

В. А

I = AcosФ/R .dB /dt

But it isn't reasonable to say that we can create a magnetic field by having a flow of current and this can be used to make more current because the current generated due to change in magnetic field created by increase/decrease in flow of current will be in a direction such that it will counter act the change in magnetic field caused by increase/decrease in current flow.(lenz's law).

We were unable to transcribe this image

Ф= В. А

I = Acos dB Rd

3 0

3 years ago

Two concentric current loops lie in the same plane. The smaller loop has a radius of 3.4 cmcm and a current of 12 AA. The bigger

Free_Kalibri [48]

Answer:

Explanation:

Given that,

Current in loops are

i1 = 12A

i2 = 20A

The loops are 3.4cm apart

The magnetic field at the center is found to be zero, so when want to find the radius of bigger loop

Magnetic Field is given as

B= μoi/2πr

Where,

μo is a constant = 4π×10^-7 Tm/A

r is the distance between the two wires

i is the current in the wires

B is the magnetic field

NOTE

Field due to large loop should be equal to the smaller loop.

B1 = B2

μo•i1 / 2π•r1 = μo•i2 / 2π•r2

Then, μo, 2π cancels out, so we have

i1 / r1 = i2 / r2

Make r2 subject of formula

i1•r2 = i2•r1

r2 = i2•r1 / i2

r2 = 20×3.4/12

r2 = 5.67cm

The radius of the bigger loop is 5.67cm.

4 0

3 years ago