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3 years ago

What best describes the relationship between the frequency of an oscillation and the period of the oscillation?

Physics

1 answer:

ZanzabumX [31]3 years ago

4 0

Explanation:

Let f is the frequency of an oscillation and T is the period of the oscillation. There exists an inverse relationship between the frequency and the time period of the oscillation. Mathematically, it is given by :

$f=\dfrac{1}{T}$

Also, $f=\dfrac{\omega}{2\pi}$

So,

$T=\dfrac{2\pi}{\omega}$

The time taken to complete one oscillation is called the period of the oscillation and the number of oscillation is called the frequency if an oscillation.

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Which of the following refers to a force acting toward the center of a circular

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Answer:

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3 years ago

Welcome to this IE. You may navigate to any page you've seen already using the IE Outline tab on the right. A particle beam is m

Genrish500 [490]

Answer:

the magnitude of a uniform electric field that will stop these protons in a distance of 2 m is 10143.57 V/m or 1.01 × 10⁴ V/m

Explanation:

Given the data in the question;

Kinetic energy of each proton that makes up the beam = 3.25 × 10⁻¹⁵ J

Mass of proton = 1.673 × 10⁻²⁷ kg

Charge of proton = 1.602 × 10⁻¹⁹ C

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we know that

Kinetic Energy = Charge of proton × Potential difference ΔV

Potential difference ΔV = Kinetic Energy / Charge of proton

we substitute

Potential difference ΔV = ( 3.25 × 10⁻¹⁵ ) / ( 1.602 × 10⁻¹⁹ )

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Now, the magnitude of a uniform electric field that will stop these protons in a distance of 2 m will be;

E = Potential difference ΔV / distance d

we substitute

E = 20287.14 V / 2 m

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3 0

3 years ago

Puede ser la suma de dos vectores de distinta magnitud igual a 0

True [87]

Answer:

Falso. Se requiere de dos vectores de igual magnitud pero antiparalelos entre sí.

Explanation:

Un vector es un elemento caracterizado por tener magnitud y dirección, sea $\vec v \in \mathbb{R}$ un vector tal que la resultante sea $\vec O$ (vector nulo). Por Álgebra de los Reales se sabe que todo vector tiene su inverso, es decir, que existe un vector $-\vec v$ tal que:

$\vec v + (-\vec v) = \vec O$

$(v_{x}, v_{y}) + [-(v_{x},v_{y})] = (0,0)$

$(v_{x}-v_{x}, v_{y}-v_{y}) = (0, 0)$

Esto significa, que el siguiente sistema de ecuaciones debe satisfacerse:

$v_{x}-v_{x} = 0$

$v_{y}-v_{y} = 0$

Se requiere de dos vectores de igual magnitud pero antiparalelos entre sí. En consecuencia, la anterior afirmación es falsa.

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