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mote1985 [20]
3 years ago
10

Which wave causes the medium to vibrate only in a direction parallel to the wave’s motion?

Physics
2 answers:
andreyandreev [35.5K]3 years ago
6 0
When the vibration is in a direction parallel to wave's motion that is a Longitudinal wave  (C).

But When the vibration is in a direction perpendicular to wave's motion then it is Transverse wave.

alexira [117]3 years ago
5 0

Answer: The correct option is C.

Explanation:

Longitudinal wave is a wave in which the particles of the medium vibrate parallel to the direction of the wave. For example, sound wave. Longitudinal wave needs medium to travel. It can travel in solid, liquid and gas.

Transverse wave is a wave in which the particles of the medium move perpendicular to the direction of the wave. For example, light wave. Transverse wave does not need any medium to travel.

Therefore, longitudinal wave causes the medium to vibrate only in a direction parallel to the wave's motion.

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Two football players move in a straight line directly toward one another. Their equations of motion are as follows:
iren [92.7K]

The time when the two players will collide is 0.96 s.

The equation of motion of the two players is given as;

x1 = 0.1 m + (–3.9 m/s )t

x2 = –6.3 m + (2.8 m/s )t

The time when the two players collide, their displacement is equal or the difference in their position will be zero.

X_1 - X_2 = 0\\\\0.1 - 3.9 t - (-6.3 + 2.8t) = 0\\\\0.1 -3.9t + 6.3 -2.8t = 0\\\\6.4 -6.7t = 0\\\\6.7t = 6.4\\\\t = \frac{6.4}{6.7} = 0.96 \ s

Thus, the time when the two players will collide is 0.96 s.

Learn more here: brainly.com/question/18033352

6 0
2 years ago
A mass weighting 48 lbs stretches a spring 6 inches. The mass is in a medium that exerts a viscous resistance of 27 lbs when the
Mademuasel [1]

Answer:

a)

u(t)=0.499ft.e^{-\frac{144.76lb/s}{2(48lb)}t}cos(\omega t)\\\\u(t)=0.499ft.e^{-1.5t}cos(\omega t)

b)

m = 48lb

c)

b = 144.76lb

Explanation:

The general equation of a damping oscillate motion is given by:

u(t)=u_oe^{-\frac{b}{2m}t}cos(\omega t-\alpha)    (1)

uo: initial position

m: mass of the block

b: damping coefficient

w: angular frequency

α: initial phase

a. With the information given in the statement you replace the values of the parameters in (1). But first, you calculate the constant b by using the information about the viscous resistance force:

|F_{vis}|=bv\\\\b=\frac{|F_{vis}|}{v}\\\\|F_{vis}|=27lbs=27*32.17ft.lb/s^2=868.59ft.lb/s^2\\\\b=\frac{868.59}{6}lb/s=144.76lb/s

Then, you obtain by replacing in (1):

6in = 0.499 ft

u(t)=0.499ft.e^{-\frac{144.76lb/s}{2(48lb)}t}cos(\omega t)\\\\u(t)=0.499ft.e^{-1.5t}cos(\omega t)

b.

mass, m = 48lb

c.

b = 144.76 lb/s

8 0
3 years ago
Atmospheric pressure on the peak of Mt. Everest can be as low as 0.197 atm, which is why
lbvjy [14]

Answer:2,030

Explanation:

40 atm x 10.0 L = 400

400/0.197 atm = 2,030

7 0
3 years ago
What charge appears on each plate of a 10.0 μF parallel plate capacitor, when it is charged to 110 V?
elena-14-01-66 [18.8K]

Answer:

charge, q = ± 1.1 mC

Given:

Capacitance, C = 10.0\micro F = 10.0\times 10^{- 6} F

Voltage, V = 110 V

Solution:

The charge on the capacitor plates can be calculated by using the definition of capacitance as :

q ∝ V

where

q = charge

V = potential difference or Voltage

Therefore,

q = CV

Now, charge, q :

q = 10.0\times 10^{- 6}\times 110 = 1100\micro C = 1.1 mC

Therefore, the charge on the positive plate is:

q = + 1.1 mC

the charge on the negative plate is:

q = - 1.1 mC

8 0
3 years ago
What does 760mmHg represents??​
malfutka [58]

Explanation:

760 mmHg (millimeters of mercury) is a measure of atmospheric pressure.  It represents the height of a column of mercury at which the static pressure at the bottom is equal to the atmospheric pressure.

1 atm = 760 mmHg = 101,325 Pa = 14.7 psi

8 0
3 years ago
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