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mote1985 [20]
3 years ago
10

Which wave causes the medium to vibrate only in a direction parallel to the wave’s motion?

Physics
2 answers:
andreyandreev [35.5K]3 years ago
6 0
When the vibration is in a direction parallel to wave's motion that is a Longitudinal wave  (C).

But When the vibration is in a direction perpendicular to wave's motion then it is Transverse wave.

alexira [117]3 years ago
5 0

Answer: The correct option is C.

Explanation:

Longitudinal wave is a wave in which the particles of the medium vibrate parallel to the direction of the wave. For example, sound wave. Longitudinal wave needs medium to travel. It can travel in solid, liquid and gas.

Transverse wave is a wave in which the particles of the medium move perpendicular to the direction of the wave. For example, light wave. Transverse wave does not need any medium to travel.

Therefore, longitudinal wave causes the medium to vibrate only in a direction parallel to the wave's motion.

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krok68 [10]

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You would be required to have bodily injury liability insurance in Florida if you are involved in a crash where your vehicle has caused damage to the property of others.

 

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6 0
3 years ago
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Which of these habitats has a highly salinity
Llana [10]
The answer for APEX Learning is Ocean
7 0
3 years ago
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During a free fall Swati was accelerating at -9.8m/s2. After 120 seconds how far did she travel? Use the formula =1/2 *
marta [7]
Distance fallen = 1/2 ( V initial + V final ) *t
We know
a = -9.8 m/s2
t=120s

To find distance fallen, we need to find V final
Use the equation
V final = V initial + a*t
Substitute known values
V final = 0 + (-9.8)(120)
V final = -1176 m/s

Then plug known values to distance fallen equation
Distance fallen = 1/2 ( 0 + 1176 )(120)
= 1/2(1776)(120)
=106,560 m

This way plugging into distance equation is actually the long way. A faster way is to plug the values into
Distance fallen = V initial * t + 1/2(a*t)
We won't need to find V final using another equation.

But anyways, good luck!



4 0
3 years ago
A block with mass 0.5 kg is forced against a horizontal spring of negligible mass, compressing the spring a distance of 0.2 m. W
lianna [129]

Answer:

So coefficient of kinetic friction will be equal to 0.4081

Explanation:

We have given mass of the block m = 0.5 kg

The spring is compressed by length x = 0.2 m

Spring constant of the sprig k = 100 N/m

Blocks moves a horizontal distance of s = 1 m

Work done in stretching the spring is equal to W=\frac{1}{2}kx^2=\frac{1}{2}\times 100\times 0.2^2=2J

This energy will be equal to kinetic energy of the block

And this kinetic energy must be equal to work done by the frictional force

So \mu mg\times s=2

\mu\times  0.5\times 9.8\times 1=2

\mu =0.4081

So coefficient of kinetic friction will be equal to 0.4081

5 0
3 years ago
Help with physics projectile motion​
BlackZzzverrR [31]

Answer:

10.4 m/s

Explanation:

First, find the time it takes for the projectile to fall 6 m.

Given:

y₀ = 6 m

y = 0 m

v₀ = 0 m/s

a = -9.8 m/s²

Find: t

y = y₀ + v₀ t + ½ at²

(0 m) = (6 m) + (0 m/s) t + ½ (-9.8 m/s²) t²

t = 1.11 s

Now find the horizontal position of the target after that time:

Given:

x₀ = 6 m

v₀ = 5 m/s

a = 0 m/s²

t = 1.11 s

Find: x

x = x₀ + v₀ t + ½ at²

x = (6 m) + (5 m/s) (1.11 s) + ½ (0 m/s²) (1.11 s)²

x = 11.5 m

Finally, find the launch velocity needed to travel that distance in that time.

Given:

x₀ = 0 m

x = 11.5 m

t = 1.11 s

a = 0 m/s²

Find: v₀

(11.5 m) = (0 m) + v₀ (1.11 s) + ½ (0 m/s²) (1.11 s)²

v₀ = 10.4 m/s

3 0
3 years ago
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