x = player1
y = player 2
z = player 3
y = 2x or 1/2 y =x
y = z-10 or z = y+10
x+y+z=70
substitute x= 1/2 y and z = y+10 into the above equation
1/2y + y + y+10 = 70
2.5 y + 10 = 70
subtract 10 from each side
2.5 y = 60
divide by 2.5 on each side
y = 60/2.5
y =24
x = 1/2 y
x = 1/2 *24 = 12
z = y+10 = 24+10 = 34
The three players scored 12, 24, 34
X + x + 24 = 58
x = (58-24)/2=17
the first number is 17 and the second number is the sum of 17 and 28. Finding it has been left as an exercise for the reader.
Answer:
The answer is 1
Step-by-step explanation:
2(a+7)−7=9
Step 1: Simplify both sides of the equation.
2(a+7)−7=9
(2)(a)+(2)(7)+−7=9(Distribute)
2a+14+−7=9
(2a)+(14+−7)=9(Combine Like Terms)
2a+7=9
2a+7=9
Step 2: Subtract 7 from both sides.
2a+7−7=9−7
2a=2
Step 3: Divide both sides by 2.
2a
2
=
2
2
a=1
The answer should be "The puppy gained weight only."