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3 years ago

Which is the graph of y = 1/x?

Mathematics

1 answer:

irina1246 [14]3 years ago

6 0

answer: the first graph

explanation:

it would not be the second one because it is a slope (y = mx + b) and so would be the third choice.

i don't think it would be the last one because it's going only up to 40. which the equation say only y = 1/x and it's not a big number equation.

hope this helps! ❤ from peachimin

i attached this image which is sorta similar to the the to this equation:

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1) Find the value of x.

Stells [14]

x=8

Explanation:

the opposite side is 72, which means I have to make 9x end up equaling 72.

72÷9

////

72/9

9×8=72

Therefore

the value of x is 8.

6 0

2 years ago

Which expression is equivalent to 8x+5-10x+4y

Feliz [49]

Answer:

add your x variables together

5 0

3 years ago

A triangle is removed from the rectangle. Find the area of the remaining figure.

Mariulka [41]

Answer

C) 160 in^2

Step by step explanation

First, let's find the area of the rectangle.

Area of a rectangle = length x width

The area of the rectangle = 20 * 10

= 200 in^2

Now let's find the area of the triangle that is removed.

Area of a triangle = 1/2 base * height.

Here base = 10 and height = 8. Plug in these values into the formula, we get

Area of the triangle = 1/2 * 10*8

= 5* 8

The area of the triangle = 40 in^2

The area of the remaining figure = Area of the rectangle - area of the triangle

= 200 - 40

= 160 in^2

The answer is "160 in^2"

Thank you.

5 0

3 years ago

Is due today Help!!! Algebra ll

guapka [62]

$-7x-9y=-8$

$5x+6y=4$

$-35x-45y=-40$

$35x+42y=28$

$-3y=-12$

$y=4$

$5x+6(4)=4$

$5x+24=4$

$5x=-20$

$x=-4$

$(-4,4)$

Hope this helps.

頑張って!

7 0

3 years ago

If a certain cannon is fired from a height of 8.8 meters above the ground, at a certain angle, the height of the cannonball ab

Dennis_Churaev [7]

Answer:

It would take approximately 6.50 second for the cannonball to strike the ground.

Step-by-step explanation:

Consider the provided function.

$h(t)=-4.9t^2+30.5t+8.8$

We need to find the time takes for the cannonball to strike the ground.

Substitute h(t) = 0 in above function.

$-4.9t^2+30.5t+8.8=0$

Multiply both sides by 10.

$-49t^2+305t+88=0$

For a quadratic equation of the form $ax^2+bx+c=0$ the solutions are: $x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

Substitute a = -49, b = 305 and c=88

$t=\frac{-305+\sqrt{305^2-4\left(-49\right)88}}{2\left(-49\right)}=-\frac{-305+\sqrt{110273}}{98}\\t = \frac{-305-\sqrt{305^2-4\left(-49\right)88}}{2\left(-49\right)}= \frac{305+\sqrt{110273}}{98}$

Ignore the negative value of t as time can't be a negative number.

Thus,

$t=\frac{305+\sqrt{110273}}{98}\approx6.50$

Hence, it would take approximately 6.50 second for the cannonball to strike the ground.

6 0

3 years ago