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Lesechka [4]
4 years ago
11

What is the solution of 3+x-2/x-3

Mathematics
1 answer:
notka56 [123]4 years ago
5 0
I think
= x^2-11
______
x-3
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3 years ago
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5(7 + 3x) - 12 how to simplify​
motikmotik

To solve this we need to use this formula:

a(b+c)=ab+ac

5(7+3x)-12=35+15x-12=15x+23

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3 years ago
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How would I categorize numbers? For example, what category would √23 fit into? Thankssss
alexandr1967 [171]

Answer:

  positive, real, irrational, algebraic

Step-by-step explanation:

Numbers are categorized various ways. Some categories include ...

  prime, composite

  real, complex

  integer, rational, irrational

  whole number, natural number

  positive, negative, zero

  algebraic, non-algebraic*

√23 is the positive, real, irrational root of a prime number. It is an algebraic number.

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* An algebraic number is a root of a polynomial with integer coefficients.

√23 is a root of x^2 -23 = 0.

4 0
3 years ago
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Find the solution set of the following quadratic equations using the quadratic formula.
oksian1 [2.3K]

Answer:

<h3>                1)  x_1=\dfrac{7+\sqrt{13}}2\,,\quad x_2=\dfrac{7-\sqrt{13}}2</h3><h3>                2)   x_1=-\dfrac13\,,\quad x_2=-3    </h3>

Step-by-step explanation:

<h3>1)</h3>

x^2 - 7x + 9 = 0\quad\implies\quad a=1\,,\ b = -7\,,\ c=9\\\\x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}=\dfrac{-(-7)\pm\sqrt{(-7)^2-4\cdot1\cdot9}}{2\cdot1}=\dfrac{7\pm\sqrt{49-36}}2\\\\x_1=\dfrac{7+\sqrt{13}}2\,,\quad x_2=\dfrac{7-\sqrt{13}}2

<h3>2)</h3><h3>3x^2 + 10x=-3\\\\3x^2+10x+3=0\quad\implies\quad a=3\,,\ b =10\,,\ c=3\\\\x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}=\dfrac{-10\pm\sqrt{10^2-4\cdot3\cdot3}}{2\cdot3}= \dfrac{-10\pm\sqrt{100-36}}6\\\\x_1=\dfrac{-10+\sqrt{64}}6=\dfrac{-10+8}6=-\dfrac13\,,\qquad x_2=\dfrac{-10-8}6=-3</h3>
7 0
3 years ago
What is the answer to 5−2x^2=37
Strike441 [17]

Answer:

x= 4i or -4i

Step-by-step explanation:

Isolate the variable by dividing each side by factors that don't contain the variable.

Hope this helped :)

4 0
3 years ago
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