The perimeter = sum of all sides
= 120 + 80 + 50
= 250
So 250 - 3
247
Left space for gate
Now cost of fencing = Rs 20/per meter
= 247 × 20
= Rs 4,940
Now the area of the triangular park can be found using heron's formula
S = (a+b+c)/2
S = (120+80+50)/2
S = 250/2
S = 125
Now
Herons formula = √s(s-a)(s-b)(s-c)
√125(125-120)(125-80)(120-50)
√125(5)(45)(70)
√5×5×5×5×5×3×3×5×14
After Making pairs
5×5×5×3√14
375√14
Therefore 375√14m is the area of the triangular park
Must click thanks and mark brainliest
i think its 2.5 because 15/6= 2.5 so 2.5t=h and the equation is kt=h so 2.5 makes the most sense.
I hope this helps
Answer:
C
Step-by-step explanation:
Answer:
f(2) = -6
General Formulas and Concepts:
Order of Operations: BPEMDAS
Substitution and Evaluation
Step-by-step explanation:
<u>Step 1: Define</u>
f(x) = -2x² + 4x - 6
f(2) is x = 2
<u>Step 2: Solve</u>
- Substitute: f(2) = -2(2)² + 4(2) - 6
- Exponents: f(2) = -2(4) + 4(2) - 6
- Multiply: f(2) = -8 + 8 - 6
- Add: f(2) = -6
