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MA_775_DIABLO [31]
3 years ago
14

A solution which is 38.0% w/w in k2cro4 has a specific gravity of 1.37. calculate the concentration in terms of molarity of chro

mate ion.
Mathematics
1 answer:
Makovka662 [10]3 years ago
7 0
When in aqueous solution, K2CrO4 dissociates into ions. It dissociates into:

K2CrO4 = 2K+1 + CrO4-1

We do as follows:

Molarity = mol / L = 0.38 g/g solution ( 1.37 g/mL ) ( 1 mol / 194.19 g ) ( 1 mol CrO4-1 / 1 mol K2CrO4 ) ( 1000 mL / 1 L ) =  2.68 M
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Answer:

It will take an interest rate of 8.1% to get 150% of the initial investment in just 5 years.

Step-by-step explanation:

Use the formula for continuous compounding

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We are given t=5, and percent increase on the initial P, so we can solve for r

X(5) = 1.5P=Pe^{r\cdot5}\\1.5=e^{r\cdot5}\\\ln 1.5=\ln e ^{5r}\\\ln 1.5=5r\\r = \frac{\ln 1.5}{5}=0.081\rightarrow 8.1\%

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