It's called "Ionic compound"
<u>We are given:</u><u>_______________________________________________</u>
Volume of Gas (V) = 2.5L
Pressure (P) = 1.2 atm
Temperature (T) = 25°C OR 25+273 = 298 K
Universal Gravitational Constant (R) = 0.0821
<u>Solving for number of moles:</u><u>___________________________________</u>
From the Ideal Gas Equation,
PV = nRT
(1.2)(2.5) = n(0.0821)(298) [plugging the given values]
n = [(1.2)(2.5)] / [0.0821*298]
n = 300 / [298*8.21]
n = 0.12 moles
Hence, there are 0.12 moles of Oxygen in 2.5L of 1.2 atm gas when the temperature is 25°C
Answer:
20 L of Cl₂
Solution:
The reaction is as follow,
H₂C₂ + 2 Cl₂ → H₂C₂Cl₄
According to equation,
167.84 g (1 mole) H₂C₂Cl₄ is produced by = 44.8 L (2 mole) of Cl₂
So,
75 g of H₂C₂Cl₄ will be produced by = X L of Cl₂
Solving for X,
X = (44.8 L × 75 g) ÷ 167.84 g
X = 20 L of Cl₂
Answer:
1. Sunlight path becoming visible when lots of dust particles are suspended in the air such as light passing through the canopy of a dense forest.
2.When a torch is switched on in a foggy environment, the path of the light becomes visible.
Answer:
They increase the concentration of the reactants
Explanation:
