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Mathematics

2 answers:

Katen [24]2 years ago

5 0

Answer:12

Step-by-step explanation: Using Prime Factorization Method

1728=2*2*2*2*2*2*3*3*3

1728=(2*2*2)(2*2*2)(3*3*3)

1728=2^3 *2^3*2

Cube root the number above you would get 2*2*3=12.

Nady [450]2 years ago

3 0

Answer:

Step-by-step explanation:

∛1728 = ∛2*2*2*2*2*2*3*3*3*3 = 2*2*3 = 12

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The sum of two numbers is odd. Can the quotient of the two numbers be an odd number?

Natalka [10]

Answer: No.

Step-by-step explanation:

I guess that here we have the statement:

If the sum of two numbers is odd----> can their quotient be an odd number?

first, for n an integer number, we have that:

an odd number can be written as 2n + 1

an even number can be written as 2n.

The sum of two numbers is only odd if one of them is odd and the other even.

Then we have a number that is 2n and other that is 2k + 1, for n and k integer numbers.

Now, let's see if the quotient can also be an odd number.

One way to think this is:

There is an odd number such that when we multiply it by another odd number, the result is an even number?

no, and i can prove it as:

let 2k + 1 be an odd number, and 2j + 1 other.

the product is:

(2k + 1)*(2j + 1) = 2*(2*k*j + k + j) + 1

and as k and j are integers, also does 2*k*j + k + j, so:

2*(2*k*j + k + j) + 1 is an odd number.

This says that the product of two odd numbers is always odd, then we never can have that the quotient between an even number and an odd number is odd.

4 0

3 years ago

PLEASEE HELP!!

Alex777 [14]

Answer:

Step-by-step explanation:

<h3>to understand this</h3><h3>you need to know about:</h3>

quadratic equation
quadratic equation word problems
solving quadratic

<h3>given:</h3>

h(t) = -4t² + 12t + 100

<h3>to solve:</h3>

<h3>tips and formulas:</h3>

<u>the</u><u> </u><u>Ball</u><u> </u><u>will</u><u> </u><u>hit </u><u>the</u><u> ground</u><u> </u><u>when</u><u> </u><u>the</u><u> height</u><u> is</u><u> </u><u>0</u>
<u>solving</u><u> </u><u>quadratics </u><u>using</u><u> </u><u>quadratic</u><u> formula</u>
<u>PEMDAS</u>

<h3>let's solve: </h3>

$step - 1 : \: define$