All categories

4 years ago

Explain how to evaluate a + b ÷ c, when a = 1 2/5, b = 2 2/5, and c = 3/4. You do not have to compute the values.

Mathematics

1 answer:

raketka [301]4 years ago

3 0

Answer:

The correct answer is: $4\frac{3}{5}$

Step-by-step explanation:

According to the rule of BODMAS, division is done before addition.

So, in a + b ÷ c, we will first calculate, b ÷ c

Given b = $2\frac{2}{5}$ = $\frac{12}{5}$ , c = $\frac{3}{4}$ .

So, $\frac{b}{c}$ = $\frac{12}{5}$ ÷ $\frac{3}{4}$

So, $\frac{b}{c} = \frac{12}{5} \times\frac{4}{3}$ , as the numerator and denominator gets reversed as division is changed to multiplication.

So, $\frac{b}{c} = \frac{16}{5}$ .

Next the value of a to $\frac{b}{c}$ , where, $a = 1\frac{2}{5} = \frac{7}{5}$ , we get,

$\frac{7}{5} +\frac{16}{5} = \frac{23}{5} = 4\frac{3}{5}$ .

You might be interested in

Two pillars have been delivered for the support of a shade structure in the backyard. they are both ten feet tall and the cross

BartSMP [9]

The steps to determine whether the pillars have the same volume are;

First, we must know that the volume of an object of uniform surface area is the product of its Area and height.

The uniform area of each pillar is then evaluated and if equal;

Both pillars can be concluded to have the same volume.

We must first recall that for various shapes, the volume of the shape is a function of its height.

For example: a A cylinderical pillar and a rectangular prism pillar;

Volume of a cylinder = πr²h

Volume of a Cuboid = l × w × h

Since h = h.

Therefore, for both pillars to have the same volume; their Areas must be equal.

πr² = l × w

Learn more about Area and volume here

brainly.com/question/987829

#SPJ4

3 0

2 years ago

Write the equation -4x^2+9y^2+32x+36y-64=0 in standard form. Please show me each step of the process!

IgorC [24]

Hey there, hope I can help!

$-4x^2+9y^2+32x+36y-64=0$

$\mathrm{Add\:}64\mathrm{\:to\:both\:sides} \ \textgreater \ 9y^2+32x+36y-4x^2=64$

$\mathrm{Factor\:out\:coefficient\:of\:square\:terms} \ \textgreater \ -4\left(x^2-8x\right)+9\left(y^2+4y\right)=64$

$\mathrm{Divide\:by\:coefficient\:of\:square\:terms:\:}4$
$-\left(x^2-8x\right)+\frac{9}{4}\left(y^2+4y\right)=16$

$\mathrm{Divide\:by\:coefficient\:of\:square\:terms:\:}9$
$-\frac{1}{9}\left(x^2-8x\right)+\frac{1}{4}\left(y^2+4y\right)=\frac{16}{9}$

$\mathrm{Convert}\:x\:\mathrm{to\:square\:form}$
$-\frac{1}{9}\left(x^2-8x+16\right)+\frac{1}{4}\left(y^2+4y\right)=\frac{16}{9}-\frac{1}{9}\left(16\right)$

$\mathrm{Convert\:to\:square\:form}$
$-\frac{1}{9}\left(x-4\right)^2+\frac{1}{4}\left(y^2+4y\right)=\frac{16}{9}-\frac{1}{9}\left(16\right)$

$\mathrm{Convert}\:y\:\mathrm{to\:square\:form}$
$-\frac{1}{9}\left(x-4\right)^2+\frac{1}{4}\left(y^2+4y+4\right)=\frac{16}{9}-\frac{1}{9}\left(16\right)+\frac{1}{4}\left(4\right)$

$\mathrm{Convert\:to\:square\:form}$
$-\frac{1}{9}\left(x-4\right)^2+\frac{1}{4}\left(y+2\right)^2=\frac{16}{9}-\frac{1}{9}\left(16\right)+\frac{1}{4}\left(4\right)$

$\mathrm{Refine\:}\frac{16}{9}-\frac{1}{9}\left(16\right)+\frac{1}{4}\left(4\right) \ \textgreater \ -\frac{1}{9}\left(x-4\right)^2+\frac{1}{4}\left(y+2\right)^2=1$

$Refine\;once\;more\;-\frac{\left(x-4\right)^2}{9}+\frac{\left(y+2\right)^2}{4}=1$

For me I used
$\frac{\left(y-k\right)^2}{a^2}-\frac{\left(x-h\right)^2}{b^2}= 1$
$As\;\mathrm{it\;\:is\:the\:standard\:equation\:for\:an\:up-down\:facing\:hyperbola}$

I know yours is an equation which is why I did not go any further because this is the standard form you are looking for. I would rewrite mine to get my hyperbola standard form. However the one I have provided is the form you need where mine would be.
$\frac{\left(y-\left(-2\right)\right)^2}{2^2}-\frac{\left(x-4\right)^2}{3^2}=1$

Hope this helps!

4 0

4 years ago

A video game console that is normally priced at 269.99 has been marked down by 33% of its original price. If the sales tax is 8.

larisa86 [58]

Answer:

$5.99

Step-by-step explanation:

I am Majoring in math and Personal Finance

7 0

3 years ago

daniel is using a scale factor of 10 to enlarge a class photo that measures 3.5 inches by 5 inches what are The dimensions Love

Sholpan [36]