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castortr0y [4]
3 years ago
7

Let H be the set of all polynomials having degree at most 4 and rational coefficients. Determine whether H is a vector space. If

it is not a vector space, determine which of the following properties it fails to satisfy. A: Contains zero vector B: Closed under vector addition C: Closed under multiplication by scalars
Mathematics
1 answer:
Verizon [17]3 years ago
7 0

Answer:

Yes. It is a vector space over the field of rational numbers \mathbb{Q}

Step-by-step explanation:

An element p of the set H has the form

p(x)=a_{0}+a_{1}x+a_{2}x^{2}+a_{3}x^{3}+a_{4}x^{4}

where a_{0},a_{1},a_{2},a_{3},a_{4} are rational coefficients.

The operations of addition and scalar multiplication are defined as follows:

p(x)+q(x)=(a_{0}+a_{1}x+a_{2}x^{2}+a_{3}x^{3}+x_{4}x^4)+(b_{0}+b_{1}x+b_{2}x^{2}+b_{3}x^{3}+b_{4}x^{4})=(a_{0}+b_{0})+(a_{1}+b_{1})x+(a_{2}+b_{2})x^{2}+(a_{3}+b_{3})x^{3}+(a_{4}+b_{4})x^{4}

\lambda p(x)=\lambda (a_{0}+a_{1}x+a_{2}x^{2}+a_{3}x^{3}+a_{4}x^{4})=\lambda a_{0}+\lambda a_{1}x+\lambda a_{2}x^{2}+\lambda a_{3}x^{3}+\lambda a_{4}x^{4}

The properties that H, together the operations of vector addition and scalar multiplication,  must satisfy are:

  1. Conmutativity
  2. Associativity of addition and scalar multiplication
  3. Additive Identity
  4. Additive inverse
  5. Multiplicative Identity
  6. Distributive properties.

This is not difficult with the definitions given. The most important part is to show that H has a additive identity, which is the zero polynomial, that is closed under vector addition and scalar multiplication. This last properties comes from the fact that \mathbb{Q} is a field, then it is closed under sum and multiplication.

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The width of the garden is approximately 3.987 meters

Part B

Please find attached the drawing of the solution

Step-by-step explanation:

Part A

The given parameters are;

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The width of the garden to be built in the yard = Uniform width

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The width of the rectangular area of grass at the center, w = 25 - 2·x

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The area of the rectangular backyard, A = 750 = (30 - 2·x)·(25 - 2·x) + (30 - 2·x)·(25 - 2·x)  = 2 × (30 - 2·x)·(25 - 2·x) = 8·x² - 220·x + 1,500

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Part B

The drawing of the solution created with MS Visio is attached

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