The atmosphere is about 21% oxygen. At a pressure of 749 torr, what is the partial pressure of O2?
1 answer:
Answer:
157.29 Torr
Explanation:
This question may be solved by the mole fraction.
Mole fraction → Moles of gas / Total moles = Partial pressure of gas / Total pressure
If the atmosphere is about 21% you assume that the mole fraction is 0.21 so:
0.21 = Partial pressure of gas / Total pressure
0.21 = Partial pressure of gas / 749 Torr
Partial pressure of the gas = 749 Torr . 0.21 → 157.29 Torr
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M1 = 17.45 M
M2 = 0.83 M
V2 = 250 ml
M1. V1= M2. V2
V1 = (M2. V2)/M1 = (0.83× 250)/ 17.45= 11.89 ml
The number in standard form is 0.480
Im sorry i dont know that one
