Answer:
Group B elements
Explanation:
Group B metals are referred to as transition metals. They are located in the middle of the periodic table between Group IIA and Group IIIA. They provide transition between the "base formers" on the left and "acid formers" on the right.
Answer:
MoClBr₂
Explanation:
First we calculate the mass of bromine in the compound:
- 300.00 g - (82.46224 g + 45.741 g) = 171.79676 g
Then we<u> calculate the number of moles of each element</u>, using their <em>respective molar masses</em>:
- 82.46224 g Mo ÷ 95.95 g/mol = 0.9594 mol Mo
- 45.741 g Cl ÷ 35.45 g/mol = 1.290 mol Cl
- 171.79676 g Br ÷79.9 g/mol = 2.150 mol Br
Now we <u>divide those numbers of moles by the lowest number among them</u>:
- 0.9594 mol Mo / 0.9594 = 1
- 1.290 mol Cl / 0.9594 = 1.34 ≅ 1
- 2.150 mol Br / 0.9594 = 2.24 ≅ 2
Meaning the empirical formula is MoClBr₂.
I will have to go with carbon monoxide
Answer:
1. A state of balance in which the rates of the forward and reverse reactions are equal.
Explanation:
A dynamic equilibrium is like a cycle, the reactants change to products, but the products also change to reactants keeping the amount of each constant.
2. A state of balance in which the forward reaction stops but reverse reaction continues.
In this statement there isnt a equilibrium. The products will change to reactants until the reaction stops.
3. A state of balance in which the forward reaction continues but reverse reaction stops.
Here the reactants will change to products until the reaction stops.
4. A state of balance in which the forward and reverse reactions stop.
In this case the reaction has stopped.
