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4 years ago

If you use 1 mole of NaOH, how much NaAl(OH)4 is produced

1 answer:

5 0

Answer:
81.97 g of NaAl(OH)₄

Solution:
The reaction for the preparation of Sodium Aluminate from Aluminium Metal and NaOH is as follow,

2 NaOH + 2 Al + 6 H₂O → 2 NaAl(OH)₄ + 3 H₂

According to this equation,

2 Moles of NaOH produces = 163.94 g (2 mole) of NaAl(OH)₄
So,
1 Mole of NaOH will produce = X g of NaAl(OH)₄

Solving for X,
X = (1 mol × 163.94 g) ÷ 2 mol

X = 81.97 g of NaAl(OH)₄

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What is the concentration of potassium ions in 153 mLof a 1.25 M K3PO4 solution

stepladder [879]

Answer:

$=3.75M$

Explanation:

Hello,

In this case, given the concentration of the potassium phosphate, we can compute the concentration of potassium ions by noticing that in one mole of salt, three moles of potassium ions are present. Moreover, since the molar units (mol/L) are in terms of potassium phosphate we should apply the following mole-mole relationship:

$1.25\frac{molK_3PO_4}{L}*\frac{3molK^+}{1molK_3PO_4} \\\\3.75\frac{molK^+}{L}=3.75M$

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4 years ago

Read 2 more answers

How many neutrons does bromine have

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4 years ago

Assuming no change in temperature and pressure, calculate the volume of O2 (in liters) required for the complete combustion of 1

Natali [406]

Answer : The number of moles of oxygen gas required are, 4.49 moles.

Explanation :

The balanced chemical reaction is:

$2C_4H_{10}(g)+13O_2(g)\rightarrow 8CO_2(g)+10H_2O(l)$

First we have to calculate the moles of butane gas.

As we know that, 1 mole of substance occupies 22.4 L volume of gas.

As, 22.4 L volume of butane gas present in 1 mole of butane gas

So, 15.5 L volume of butane gas present in $\frac{15.5}{22.4}=0.692$ mole of butane gas

Now we have to calculate the moles of oxygen gas.

From the balanced chemical reaction we conclude that,

As, 2 moles of butane gas react with 13 moles of oxygen gas

So, 0.692 moles of butane gas react with $\frac{13}{2}\times 0.692=4.49$ moles of oxygen gas

Therefore, the number of moles of oxygen gas required are, 4.49 moles.

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4 years ago

Which of these will most likely occur at the end of the experiment

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I'm not sure, I think he'll mess everything because he can't see. Let me know if this helped ‍♂️

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4 years ago

Why can metals be extracted using carbon

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If a metal is less reactive than carbon, it can be extracted from its oxide by heating with carbon. The carbon displaces the metal from the compound, and removes the oxygen from the oxide. This leaves the metal.

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2 years ago