Answer: material resources: cameras, light detection and ranging systems, radar, sensors, advanced GPS, and millions of miles of training data, and more
I don't know about the intellectual resources sorry
Answer:
Explanation:
Work, U, is equal to the force times the distance:
U = F · r
Force needed to lift the weight, is equal to the weight: F = W = m · g
so:
U = m · g · r
= 20.4kg · 9.81
· 1.50m
= 35.316 ![\frac{N}{m}](https://tex.z-dn.net/?f=%5Cfrac%7BN%7D%7Bm%7D)
= 35.316 W
During some actual expansion and compression processes in piston-cylinder devices, the gases have been are the P1= P2.
<h3>What is the pressure?</h3>
Pressure is something that has the pressure that is physical and that causes the pressure is piston-cylinder devices.
During a few real enlargements and compression procedures in piston-cylinder devices, the gases were located to meet the connection PV n = C, wherein n and C are constants.
Read more about the pressure :
brainly.com/question/25736513
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Answer:
Q= 4.6 × 10⁻³ m³/s
actual velocity will be equal to 8.39 m/s
Explanation:
density of fluid = 900 kg/m³
d₁ = 0.025 m
d₂ = 0.05 m
Δ P = -40 k N/m²
C v = 0.89
using energy equation
![\dfrac{P_1}{\gamma}+\dfrac{v_1^2}{2g} = \dfrac{P_2}{\gamma}+\dfrac{v_2^2}{2g}\\\dfrac{P_1-P_2}{\gamma}=\dfrac{v_2^2-v_1^2}{2g}\\\dfrac{-40\times 10^3\times 2}{900}=v_2^2-v_1^2](https://tex.z-dn.net/?f=%5Cdfrac%7BP_1%7D%7B%5Cgamma%7D%2B%5Cdfrac%7Bv_1%5E2%7D%7B2g%7D%20%3D%20%5Cdfrac%7BP_2%7D%7B%5Cgamma%7D%2B%5Cdfrac%7Bv_2%5E2%7D%7B2g%7D%5C%5C%5Cdfrac%7BP_1-P_2%7D%7B%5Cgamma%7D%3D%5Cdfrac%7Bv_2%5E2-v_1%5E2%7D%7B2g%7D%5C%5C%5Cdfrac%7B-40%5Ctimes%2010%5E3%5Ctimes%202%7D%7B900%7D%3Dv_2%5E2-v_1%5E2)
under ideal condition v₁² = 0
v₂² = 88.88
v₂ = 9.43 m/s
hence discharge at downstream will be
Q = Av
Q =
Q =
Q= 4.6 × 10⁻³ m³/s
we know that
![C_v =\dfrac{actual\ velocity}{theoretical\ velocity }\\0.89 =\dfrac{actual\ velocity}{9.43}\\actual\ velocity = 8.39m/s](https://tex.z-dn.net/?f=C_v%20%3D%5Cdfrac%7Bactual%5C%20velocity%7D%7Btheoretical%5C%20velocity%20%7D%5C%5C0.89%20%3D%5Cdfrac%7Bactual%5C%20velocity%7D%7B9.43%7D%5C%5Cactual%5C%20velocity%20%3D%208.39m%2Fs)
hence , actual velocity will be equal to 8.39 m/s