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Ierofanga [76]
3 years ago
8

In homes today, what is behind the reason for flashover fires occurring much more rapidly than in the past generations?

Engineering
1 answer:
garik1379 [7]3 years ago
6 0

Answer:

One of the reasons why flashover fires are more prevalent today than it was in the past is that homes and furniture today are made from materials that are far more combustible than those of previous years.

Explanation:

A flashover fire is the rapid ignition and combustion of all flammable materials in an enclosed vicinity in a very short period of time.

Thirty years ago, the average escape time from a house that was on fire is about sixteen and fifty seconds...that would be approximately seventeen minutes. Presently that figure is down to four minutes.

One of the reasons identified is that the internal and external appurtenances especially furniture in use today are more combustible than those of previous years. That is, as they burn, they produce more heat and disintegrate faster.

The reason identified for this is, old houses were made of more natural materials such as real wood etc whilst the furniture and curtains in modern houses are mostly from synthetic materials.

Cheers

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We can process oil into a lot of useful fuels to run our cars, trucks, and even airplanes. Oil is used for making lots of other
Ostrovityanka [42]

Answer:

Explanation:

Products of oil in our everyday life:

(1) Petro-Chemical Feedstock: These are by product of Refining of Oil which it is used extensively to make PET bottles, Paints, Polyester Shirts, Pocket combs e.t.c

(2) Asphalt : Used extensively to make Motor Road, highways

(3) Plastics : we use plastics in our everyday life, this is also a product of Refining of crude oil e.g PVC, Telephone casing, Tapes e.t.c

(4) Lubricating Oil/Grease : This is another product from crude oil Fractional Distillation.

(5) Propane/ Cooking Gas: This is also a product from oil which is used in our everyday life for cooking, grilling etc.

4 0
3 years ago
. . . . . . . . . . ..........
Naddika [18.5K]

Answer: Thx for points...

Explanation:

Heres Random Info About Enginnering (because why not): Engineers are involved in all aspects of interactive TV technology, from designing new cables, to creating new film emulsions, to engineering better sound quality. This technology allows viewers to select any program, film, or game from more than 500 channels. Engineers play an instrumental role in the theme park industry?

Hope This Helps Someday!

5 0
3 years ago
The wall shear stress in a fully developed flow portion of a 12-in.-diameter pipe carrying water is 2.00 lb/ft^2. Determine the
soldier1979 [14.2K]

Answer:

a) -8 lb / ft^3

b) -70.4 lb / ft^3

c) 54.4 lb / ft^3

Explanation:

Given:

- Diameter of pipe D = 12 in

- Shear stress t = 2.0 lb/ft^2

- y = 62.4 lb / ft^3

Find pressure gradient dP / dx when:

a) x is in horizontal flow direction

b) Vertical flow up

c) vertical flow down

Solution:

- dP / dx as function of shear stress and radial distance r:

                      (dP - y*L*sin(Q))/ L = 2*t / r

                      dP / L - y*sin(Q) = 2*t / r

Where            dP / L = - dP/dx,

                      dP / dx = -2*t / r - y*sin(Q)

Where            r = D /2 ,

                      dP / dx = -4*t / D - y*sin(Q)

a) Horizontal Pipe Q = 0

Hence,           dP / dx = -4*2 / 1 - 62.4*sin(0)

                      dP / dx = -8 + 0

                      dP/dx   = -8 lb / ft^3

b) Vertical pipe flow up Q = pi/2

Hence,           dP / dx = -4*2 / 1 - 62.4*sin(pi/2)

                      dP / dx = 8 - 62.4

                      dP/dx   = -70.4 lb / ft^3

c) Vertical flow down Q = -pi/2

Hence,           dP / dx = -4*2 / 1 - 62.4*sin(-pi/2)

                      dP / dx = -8 + 62.4

                      dP/dx   = 54.4 lb / ft^3                      

7 0
3 years ago
The mass fraction of eutectoid cementite in a hypoeutectoid iron-carbon alloy (just below its eutectoid temperature) is 0.109. O
Zinaida [17]

Answer:

The composition of an alloy is 0.75%wt

Explanation:

Let alloy is a hypoeutectoid alloy.

So, we can apply lever rule which is shown below.

W_{a}=\frac{C_{0} -C_{a} }{C_{b}-C_{a}  }

We know that C_{a}=0.022 and C_{b}=6.7

Given that W_{a}=0.109, we have to find C_{0}

Thus,

0.109=\frac{C_{0}-0.022 }{6.7-0.022}

Hence

C_{0}=0.75%wt

3 0
3 years ago
Define the hydraulic diameter for a rectangular duct.
Ahat [919]

Answer:

a = width of the duct (mm, in) b = height of the duct (mm, in) Hydraulic diameter of some common rectangular ducts: Hydraulic Diameter - dh - (mm) Width of Duct.

Explanation:

7 0
3 years ago
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