Answer:
Explanation:
Products of oil in our everyday life:
(1) Petro-Chemical Feedstock: These are by product of Refining of Oil which it is used extensively to make PET bottles, Paints, Polyester Shirts, Pocket combs e.t.c
(2) Asphalt : Used extensively to make Motor Road, highways 
(3) Plastics : we use plastics in our everyday life, this is also a product of Refining of crude oil e.g PVC, Telephone casing, Tapes e.t.c
(4) Lubricating Oil/Grease : This is another product from crude oil Fractional Distillation.
(5) Propane/ Cooking Gas: This is also a product from oil which is used in our everyday life for cooking, grilling etc.
 
        
             
        
        
        
Answer: Thx for points...
Explanation:
Heres Random Info About Enginnering (because why not): Engineers are involved in all aspects of interactive TV technology, from designing new cables, to creating new film emulsions, to engineering better sound quality. This technology allows viewers to select any program, film, or game from more than 500 channels. Engineers play an instrumental role in the theme park industry?
Hope This Helps Someday!
 
        
             
        
        
        
Answer:
a) -8 lb / ft^3
b) -70.4 lb / ft^3
c) 54.4 lb / ft^3
Explanation:
Given:
 - Diameter of pipe D = 12 in
 - Shear stress t = 2.0 lb/ft^2
 - y = 62.4 lb / ft^3
Find pressure gradient dP / dx when:
a) x is in horizontal flow direction
b) Vertical flow up
c) vertical flow down
Solution:
- dP / dx as function of shear stress and radial distance r:
                       (dP - y*L*sin(Q))/ L = 2*t / r
                       dP / L - y*sin(Q) = 2*t / r
Where            dP / L = - dP/dx,
                       dP / dx = -2*t / r - y*sin(Q)
Where            r = D /2 ,
                       dP / dx = -4*t / D - y*sin(Q)
a) Horizontal Pipe Q = 0
Hence,           dP / dx = -4*2 / 1 - 62.4*sin(0)
                       dP / dx = -8 + 0
                       dP/dx   = -8 lb / ft^3
b) Vertical pipe flow up Q = pi/2
Hence,           dP / dx = -4*2 / 1 - 62.4*sin(pi/2)
                       dP / dx = 8 - 62.4
                       dP/dx   = -70.4 lb / ft^3
c) Vertical flow down Q = -pi/2
 Hence,           dP / dx = -4*2 / 1 - 62.4*sin(-pi/2)
                       dP / dx = -8 + 62.4
                       dP/dx   = 54.4 lb / ft^3                      
 
        
             
        
        
        
Answer:
The composition of an alloy is 0.75%wt
Explanation:
Let alloy is a hypoeutectoid alloy.
So, we can apply lever rule which is shown below.


We know that 
 and 
Given that 
, we have to find 
Thus,

Hence
%wt
 
        
             
        
        
        
Answer:
a = width of the duct (mm, in) b = height of the duct (mm, in) Hydraulic diameter of some common rectangular ducts: Hydraulic Diameter - dh - (mm) Width of Duct.
Explanation: