Answer:
(d) all of the above
Explanation:
before cutting the screw threads the operator should lubricate all of the machine parts given in the option that is lead screw and gearbox , the ways and the cross slide and the carriage and half-nuts. we should use lubrication because it reduces the overall system friction and if friction is reduced then heat generated due to friction is also decreases which is beneficial
so option (D) will be correct because we need lubricate in all the given parts
Answer:
Java program explained below
Explanation:
FindSpecialNumber.java
import java.util.Scanner;
public class FindSpecialNumber {
public static void main(String[] args) {
//Declaring variable
int number;
/*
* Creating an Scanner class object which is used to get the inputs
* entered by the user
*/
Scanner sc = new Scanner(System.in);
//getting the input entered by the user
System.out.print("Enter a number :");
number = sc.nextInt();
/* Based on user entered number
* check whether it is special number or not
*/
if (number == -99 || number == 0 || number == 44) {
System.out.println("Special Number");
} else {
System.out.println("Not Special Number");
}
}
}
_______________
Output#1:
Enter a number :-99
Special Number
Output#2:
Enter a number :49
Not Special Number
Answer:
5E22 atoms/cm³
Explanation:
We need to find the number of moles of silicon per cm³
number of moles per cm³ = density/atomic weight = 2.33 g/cm ÷ 28.09 g/mol = 0.083 mol/cm³.
Since there are 6.022 × 10²³ atoms/mol, then the number of atoms of silicon per cm³ = number of atoms per mol × number of moles per cm³
= 6.022 × 10²³ atoms/mol × 0.083 mol/cm³
= 0.4995 × 10²³ atoms/cm³
= 4.995 × 10²² atoms/cm³
≅ 5 × 10²² atoms/cm³
= 5E22 atoms/cm³
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